Guest Posted July 31, 2009 Report Share Posted July 31, 2009 I did a little search and didn't find this one. Sorry if I missed it A farmer gave $100 to his son and asked him to buy camels, horses and sheep with the following conditions: 1. The total number of these 3 mammals has to add up to exactly 100 2. The total amount spent to buy these 100 mammals has to be exactly $100 3. The 3 types of mammals have to be bought When the son went to the market he found out that the camel costs $5, the horse costs $1, and the sheep costs $0.05 (a nickel) So how many of each type should he buy? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 Only 4 camels because they stink 16 horses 80 sheep Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 Only 4 camels because they stink 16 horses 80 sheep 4*5 + 16*1 + 80*0.05 = $40, remember the total amount has to add up to exactly $100 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 Rechecked my maths and fixed it. 19 Camels 1 Horse 80 Sheep Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 Rechecked my maths and fixed it. 19 Camels 1 Horse 80 Sheep You Got it! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 (edited) I did a little search and didn't find this one. Sorry if I missed it A farmer gave $100 to his son and asked him to buy camels, horses and sheep with the following conditions: 1. The total number of these 3 mammals has to add up to exactly 100 2. The total amount spent to buy these 100 mammals has to be exactly $100 3. The 3 types of mammals have to be bought When the son went to the market he found out that the camel costs $5, the horse costs $1, and the sheep costs $0.05 (a nickel) So how many of each type should he buy? 5C + H + 1/20S = 100 C + H + S = 100 4C - 19/20 S = 0 C = 19/80S Since C and S must be integers and C+S <=99, then it holds C = 19 S = 80. H = 100-19-80 = 1 5*19 + 1*1 + 80*.05 = 100 19 Camels, 1 Horse, 80 Sheep. Edited July 31, 2009 by eleven Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 19 camels, 1 horse, and 80 sheep Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 31, 2009 Report Share Posted July 31, 2009 80 sheep, 1 horse, and 19 camels Quote Link to comment Share on other sites More sharing options...
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Guest
I did a little search and didn't find this one. Sorry if I missed it
A farmer gave $100 to his son and asked him to buy camels, horses and sheep with the following conditions:
1. The total number of these 3 mammals has to add up to exactly 100
2. The total amount spent to buy these 100 mammals has to be exactly $100
3. The 3 types of mammals have to be bought
When the son went to the market he found out that the camel costs $5, the horse costs $1, and the sheep costs $0.05 (a nickel)
So how many of each type should he buy?
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