Guest Posted January 20, 2008 Report Share Posted January 20, 2008 This is something I saw somewhere else. Enjoy! 1. The first question with B as the correct answer is: A. 1 B. 4 C. 3 D. 2 2. The answer to Question 4 is: A. D B. A C. B D. C 3. The answer to Question 1 is: A. D B. C C. B D. A 4. The number of questions which have D as the correct answer is: A. 3 B. 2 C. 1 D. 0 5. The number of questions which have B as the correct answer is: A. 0 B. 2 C. 3 D. 1 1. C 2. D 3. B 4. C 5. B Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 20, 2008 Report Share Posted January 20, 2008 It's a possibility. 1. D 2. B 3. A 4. A 5. D Those are pretty self-explanatory except for 4. I answered with "A. 3". I justify this with questions 1 and 5 having choice D as the answer and question 3 having D (which is choice A) as the answer. Confused yet? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 20, 2008 Report Share Posted January 20, 2008 And for my second, and more correct, answer: 1. C (This states that the first question with a correct answer of B is #3.) 2. D (This states the answer to #4 is "C. 1".) 3. B (This states that the answer to #1 is C.) 4. C (This states that only one question has an answer of D.) 5. B (This states that there are two questions with correct answers of B.) First, the more obvious clues: Question #1 cannot be A or B so either #2, #3, or #2 and #3 must be B. So... Question #3 cannot be C or D. Question #4 cannot be D since it would make itself false. So... Question #2 cannot be A. Question #5 cannot be A because #1 tells us that at least one question has an answer of B. Now for trial and error: Assume the answer to question #3 is A and see how it works out. #3 is A therefore (remembering our obvious clues) #2 must be B. #2 is B therefore #1 is D and #4 is A. However, #4 cannot be A because the number of possible correct answers at this time that could be D is 2. Now start over and assume the answer to question #3 is B and see how it works out. #3 is B therefore #1 is C. #2 cannot be A and cannot be B (because #1 says so). If #2 is C, then #4 is B, but #4 cannot be B so #2 is D. #2 is D therefore #4 is C. So far, only one question is answered with B (#3), but answering #5 with D messes up #4 and from there #2 until it's all just a huge mess. Answering #5 with B makes itself true. So, in short: 1. C 2. D 3. B 4. C 5. B Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted January 21, 2008 Report Share Posted January 21, 2008 These answers are impossible: 1A 1B 3D 3C 4D 2A and 5A. Now 1D leads to 2B, 3A, 4A which is impossible. So 1 is C. 1C => 3B 3B [4A, 2B, 5C and 4B are now impossible] 4C 2D 5B. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 21, 2008 Report Share Posted January 21, 2008 These answers are impossible: 1A 1B 3D 3C 4D 2A and 5A. Now 1D leads to 2B, 3A, 4A which is impossible. So 1 is C. 1C => 3B 3B [4A, 2B, 5C and 4B are now impossible] 4C 2D 5B. I was momentarily overjoyed at the prospect of being able to tell you that you are wrong. Then I realized that your questions were not in sequential order. So I must settle for being simply joyed at the fact that we came up with the same answers. Quote Link to comment Share on other sites More sharing options...
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Guest
This is something I saw somewhere else. Enjoy!
1. The first question with B as the correct answer is:
A. 1
B. 4
C. 3
D. 2
2. The answer to Question 4 is:
A. D
B. A
C. B
D. C
3. The answer to Question 1 is:
A. D
B. C
C. B
D. A
4. The number of questions which have D as the correct answer is:
A. 3
B. 2
C. 1
D. 0
5. The number of questions which have B as the correct answer is:
A. 0
B. 2
C. 3
D. 1
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