[Yoruichi-san]

Okay...since my brain has been drained of puzzles by an alien computer in preparation for a battle for world domination (but that's another story...*cough*), I thought I'd share another one I got from a friend:

There was a toy seller who bought a certain number of balls and half that many pairs of dice. He paid $23 for each die and double that amount for each ball. He sells the items for a retail price that is 10% more than the price he paid. When he has sold all except seven objects, he has gotten back exactly the amount of money he spent. I.e the profit he'd gain by having sold all the objects is exactly the sum of the retail prices of the seven remaining objects. What is this value?

[Guest]

Did he pay 23 for each die, resulting in 46 for a pair of die or just 23 for the set (treated 1 pair as 2 dice)

[Guest]

The value left with him is 115

Price for 1 Ball and 3 Dice, in all 7 objects... totalling 115

[Guest]

Value = 2530

There was 44 balls and 22 dice he bought. At the end, he left 3 balls and 4 dice remain unsold.

So (44-3)*46*1.1 + (22-4)*23*1.1 = 2530

[Guest]

Suppose No. of Dice is D

No. of Balls is 2D

Total buying price = (D*23) + (2D*23) = 69D

Total Selling Price = 69D*1.10 = 75.9D

Now, when 7 articles left, Buying price = selling price

75.9 (D-7) = 69D

Which comes to D = 77

Buying Price = Selling price = 5313

Profit will be 7*23 = 161

[Guest]

$230,00

If Im right Ill explain better =D

EDIT: Now I see its just like woon said in the spoiler, but the question is about how much is the profit.

Edited March 2, 2009 by renan

[Guest]

Suppose No. of Dice is D

No. of Balls is 2D

Total buying price = (D*23) + (2D*23) = 69D

Total Selling Price = 69D*1.10 = 75.9D

Now, when 7 articles left, Buying price = selling price

75.9 (D-7) = 69D

Which comes to D = 77

Buying Price = Selling price = 5313

Profit will be 7*23 = 161

Do you mean Profit will be 7*23*1.1= 171.10? I am not sure about the rest of your process though, I am checking it now.

[Guest]

That is the total cost. You subtracted the total profit from the total sales

Value = 2530

There was 44 balls and 22 dice he bought. At the end, he left 3 balls and 4 dice remain unsold.

So (44-3)*46*1.1 + (22-4)*23*1.1 = 2530

[Guest]

Okay...since my brain has been drained of puzzles by an alien computer in preparation for a battle for world domination (but that's another story...*cough*), I thought I'd share another one I got from a friend:

There was a toy seller who bought a certain number of balls and half that many pairs of dice. He paid $23 for each die and double that amount for each ball. He sells the items for a retail price that is 10% more than the price he paid. When he has sold all except seven objects, he has gotten back exactly the amount of money he spent. I.e the profit he'd gain by having sold all the objects is exactly the sum of the retail prices of the seven remaining objects. What is this value?

[spolier=how about this]

Max profit = 7*46*1.1 = $354.2 (7 balls remaining)

Min profit = 7*23*1.1 = $172.10 (7 Die remaning)

I don't know where to go from here

[Guest]

Suppose No. of Dice is D

No. of Balls is 2D

Total buying price = (D*23) + (2D*23) = 69D

Total Selling Price = 69D*1.10 = 75.9D

Now, when 7 articles left, Buying price = selling price

75.9 (D-7) = 69D

Which comes to D = 77

Buying Price = Selling price = 5313

Profit will be 7*23 = 161

but i think the puzzle says

There was a toy seller who bought a certain number of balls and half that many pairs of dice

That would leave us with

x Balls and 2*x/2 dice so it means in all x balls and x dice.

he paid 46 for each ball and 23 for each dice.

46x + 23 x = 69x is his total cost.

7 Objects remaining.

which would mean 3B+4D or 5B+2D or 1B+6D [Dice sold in pairs need to be even]

6.9x = 5 *46 + 2*23 = 276

x = 40

He had 40 balls and 20 Pair of dice

his profit is 276

Edited March 3, 2009 by DeepS

[Guest]

many many aswers. Did anyone got it, Yoruichi?