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This question is adapted from a [u.S.] national math competition question at the High School level.

A fair coin has the letters a and B on its two sides.

A fair die has two sides labeled D, two labeled e and two labeled i.

Another fair coin has the letters n and r on its two sides.

The coins and die are each tossed three times.

Find the probability that the nine letters so obtained can be used to spell BrainDen.

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This question is adapted from a [u.S.] national math competition question at the High School level.

A fair coin has the letters a and B on its two sides.

A fair die has two sides labeled D, two labeled e and two labeled i.

Another fair coin has the letters n and r on its two sides.

The coins and die are each tossed three times.

Find the probability that the nine letters so obtained can be used to spell BrainDen.

edit to say: 2/8 was wrong, actually 3/8 get r + 2n: rnn, nrn, nnr. So answer is as previous poster stated. D'oh!

4.16% chance

6/8 possible outcomes of 3 flips of the first coin yeild both an 'a' and a 'B';

6/27 possible outcomes of 3 rolls of the die yield D, e, and i.

2/8 possible outcomes of 3 flips of coin 2 yield the needed r plus 2 n's.

Multiplied out this yeilds 0.04166. I simplified by assuming a 3-sided die, dunno if that messes things up.

Edited by xucam
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