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What is the largest 2-digit number that satisfies the following.

Take a 2-digit number, and square it.

Take all 3 distinct digits of the square, and reverse them.

Take the square root of this reversed square

Reverse the 2 digits which yields the original number.

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What is the largest 2-digit number that satisfies the following.

Take a 2-digit number, and square it.

Take all 3 distinct digits of the square, and reverse them.

Take the square root of this reversed square

Reverse the 2 digits which yields the original number.

31 next is 25

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What is the largest 2-digit number that satisfies the following.

Take a 2-digit number, and square it.

Take all 3 distinct digits of the square, and reverse them.

Take the square root of this reversed square

Reverse the 2 digits which yields the original number.

31

21 or

11

are the only three i found

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31 next is 25

This contains the right (according to me)

31 is what I was looking for.

By distinct, I meant that the three digits of the square were all different (although that seems to have been unclear). Thus only 13 and 31 fulfill the requirements and 31 is the largest.

25 is not going to work at any rate.

25**2 = 625, reversed is 526, sqrt(526) is 22.9xxxx

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