Guest Posted January 4, 2009 Report Share Posted January 4, 2009 (edited) my math teacher got my attention with this one, and the last puzzle reminded me of it. how can you, using whatever mathematic operator you wish but only three 0's, obtain the number 6? Edited January 4, 2009 by si:) Quote Link to comment Share on other sites More sharing options...
0 peace*out Posted January 4, 2009 Report Share Posted January 4, 2009 si:) said: my math teacher got my attention with this one, and the last puzzle reminded me of it. how can you, using whatever mathematic operator you wish but only three 0's, obtain the number 6? Reveal hidden contents 600/0+6 000+6 0+0+0+6 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 (edited) only three zeros, as in no other numbers and well, i'm portuguese. i meant operator as operation, as in something a calculator could do! not too sure about these translations Edited January 4, 2009 by si:) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 (edited) i havent really come up with a cool hint but if you want one i can try... Edited January 4, 2009 by si:) Quote Link to comment Share on other sites More sharing options...
0 peace*out Posted January 4, 2009 Report Share Posted January 4, 2009 Hint!!!! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 hmmmm..... ... ... ok Reveal hidden contents well... not all calculators can do one of the operations needed... it's an operation i learned while studying probabilities! maybe not a great hint... but... well, maybe i'll think of a better one but not right away Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 Reveal hidden contents (0! + 0! + 0!)! = (1 + 1 + 1)! = 3! =6 Or, alternatively, (cos(0) + cos(0) + cos(0))! = (1 + 1 + 1)! = 3! = 6 si:) said: hmmmm..... ... ... ok Reveal hidden contents well... not all calculators can do one of the operations needed... it's an operation i learned while studying probabilities! maybe not a great hint... but... well, maybe i'll think of a better one but not right away Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 great! the way i learnt it was the first one, but your second method was pretty cool too Quote Link to comment Share on other sites More sharing options...
0 peace*out Posted January 4, 2009 Report Share Posted January 4, 2009 an i the only one saying 'huh?' probobly... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 (edited) Reveal hidden contents the "!" operator works something like this: 5!=5*4*3*2*1 it is defined that 0!=1 that seen, 1+1+1=3 and 3!=3*2*1=6 Edited January 4, 2009 by si:) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted January 4, 2009 Report Share Posted January 4, 2009 (edited) Reveal hidden contents 0! is one and 1+1+1=3 and 3! is 3*2*1 which is six Whoops didnt read before post before Edited January 4, 2009 by Riddle Master Zack Quote Link to comment Share on other sites More sharing options...
0 peace*out Posted January 5, 2009 Report Share Posted January 5, 2009 si:) said: Reveal hidden contents the "!" operator works something like this: 5!=5*4*3*2*1 it is defined that 0!=1 that seen, 1+1+1=3 and 3!=3*2*1=6 Riddle Master Zack said: Whoops didnt read before post before Reveal hidden contents 0! is one and 1+1+1=3 and 3! is 3*2*1 which is six Thanks!!! Quote Link to comment Share on other sites More sharing options...
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my math teacher got my attention with this one, and the last puzzle reminded me of it. how can you, using whatever mathematic operator you wish but only three 0's, obtain the number 6?
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