andromeda Posted September 19, 2008 Report Share Posted September 19, 2008 (edited) A, B and X are digits (0... 9) forming numbers, so you have to guess the first digit of the number XAB! X=? Have fun! Edited September 19, 2008 by andromeda Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 (edited) x= 2, just divide by AB to get 1=x-1 nevermind, i see how the puzzle works Edited September 19, 2008 by shoeshine Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 (edited) X = A^2, if B=0 Edited September 19, 2008 by shoeshine Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 X = 4 20 x 20 = 420 - 20 Kudos to MaestroOD. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 (edited) A, B and X are digits (0... 9) forming numbers, so you have to guess the first digit of the number XAB! X=? Have fun! A=2 B=0 X=4 20 X 20 = 420 - 20 I'm not sure if I did this right.. Edit: Beckie beat me to it. Edited September 19, 2008 by Jane Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 Another answer may be: 30x30=930-30 or X=9 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 x can be 1,4 or 9 10*10 = 110 - 10 20*20 = 420 - 20 30*30 = 930 - 30 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 for A=1...3 and B=0, X=A^2. Should X be able to carry two digits then for A=1...9 and B=0, X=A^2 Are there any other solutions? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 Maybe I am wrong, but I assumed that A, B, and X were unique (no two were equal), which means that X=1 would not be a valid answer. However, since that condition wasn't stated, I can't say it is wrong. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 19, 2008 Report Share Posted September 19, 2008 for A=1...3 and B=0, X=A^2. Should X be able to carry two digits then for A=1...9 and B=0, X=A^2 Are there any other solutions? No other solutions other than X= 1,4 and 9 since AB * AB = XAB - AB we can write AB as 10A + B and XAB as 100X + 10A + B so (10A+B)2 = 100X+10+B - (10A+B) or 100A2 + B2 + 20AB = 100X or X = A2 + B2/100 + AB/5 since X is a number less than 10, (B2 + 20AB) = 100n for integer values of n the above equation is statisified only for n=0 and that means B=0 so X= A2 and since X<10 X can take values of 1, 4 and 9 Quote Link to comment Share on other sites More sharing options...
0 andromeda Posted September 19, 2008 Author Report Share Posted September 19, 2008 (edited) x can be 1,4 or 9 10*10 = 110 - 10 20*20 = 420 - 20 30*30 = 930 - 30 Actually I think that x could be number 1, but since we have XAB and not XXB, you know what I mean. So only two solutions! 20*20 = 420 - 20 30*30 = 930 - 30 Nice job! Edited September 19, 2008 by andromeda Quote Link to comment Share on other sites More sharing options...
0 andromeda Posted September 20, 2008 Author Report Share Posted September 20, 2008 (edited) X = 4 20 x 20 = 420 - 20 Kudos to MaestroOD. You bad girl! Hm... the next one will be much harder! We'll see how MaestroOD copes with that one There are two solutions for this one BTW! Edited September 20, 2008 by andromeda Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 20, 2008 Report Share Posted September 20, 2008 For A, B and X are digits (0... 9) AB X AB = XAB - AB 1) A = 0, B = 1, X=0,1,2,3,4,...,9 infact X can be anything 2) A = 1, B = 2, X = 3 3) A = 2, B = 3, X = 7 4) A = 1, B = 3, X = 4 5) A = 1, B = 4, X = 5 6) A = 1, B = 5, X = 6 7) A = 1, B = 6, X = 7 8) A = 1, B = 7, X = 8 9) A = 1, B = 8, X = 9 Quote Link to comment Share on other sites More sharing options...
Question
andromeda
A, B and X are digits (0... 9) forming numbers, so you have to guess the first digit of the number XAB!
X=?
Have fun!
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