[Guest]

Everybody knows the biggest number you can make with three 9's (9^{9^9})

But does anybody know the biggest number you can make with four 2's?

Well you know exponents are involved so the solution can have either a base of 2, 22, 222, or 2222

2222 and 222² are extremely small, relative to the solution

22²² is much greater than 22^{2^2} (22⁴)

with a base of 2 there are three possibilities:

2²²², 2^{(22^2)}, 2^{(2^22)}, 2^{(2^(2^2))}

out of those four, 2^{(2^22)} is the greatest by far.

you are left with two possibilities: 2^{(2^22)} and 22²²

if you round 22²² up to 32²² you get the equivalent of (2⁵)²²=2¹¹⁰

2^{2^22} is like taking 2 to the 4,000,000 power, therefore it is clearly the answer.

[Yoruichi-san]

(2/(2-2))^2=(2/0)^2=(2*infinity)^2

Edited August 29, 2008 by Yoruichi-san

[Guest]

Edit: Using no mathematical symbols but creative thinking y-san

[Guest]

(2/(2-2))^2=(2/0)^2=(2*infinity)^2

Nice thinking

[Guest]

Edit: Using no mathematical symbols but creative thinking y-san

Nice thinking

Well, she's our MG

[Guest]

try using bigger operators then power, like tetration or pentation.

eventualy you'll get circulation.

2 circulation 2 circulation 2 circulation 2 = infinite.

Edited August 30, 2008 by dfhwze