TwoaDay Posted July 27, 2008 Report Share Posted July 27, 2008 Four couples enter a restaurant. How many ways can they be seated at a round table so that the men and women alternate and no husband and wife sit next to each other? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 without having done any actual mathamatical figuring... Reveal hidden contents 24? Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 no, ur actually pretty far off, its probably simpler than you think Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Well crud. Just because I look like I'm good at math doesn't mean I am (right Yoruichi-san?) Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 HEY!!! no MafiaIV fights on my thread Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Reveal hidden contents 10 Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 nope ben law your wrong too, but closer Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Reveal hidden contents two, if husbands cannot sit next to their wives then they can only sit accross from them in two spots Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 (edited) Reveal hidden contents but you can reflect seating arrangements and also, there's three women a man man can sit next to so 3 combinations of the two women sitting next to a man and 6 if you reflect the seating but i don't know what the answer is Edited July 27, 2008 by lemonymelon Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Reveal hidden contents it is eight Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 the answer has been posted, but i wont tell u witch it is yet Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Reveal hidden contents 6 If we call the women w1, w2, w3 and w4 and take any one man M. Presume w4 is the wife of the man and therefore cannot sit beside him. The combinations are as follows: w1 M w2 w2 M w1 w1 M w3 w3 M w1 w2 M w3 w3 M w2 So six combinations? Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 thats not it, keep guessing Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Reveal hidden contents Yeah, stupid me. Theres at least 12, just checking if there are any more.... Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 nooo thats worse than before Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 just to claryify there are 4 men and 4 women they have to be seated alternating mwmwmwmw and the man and women in each couple cannot be sitting next to each other Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 TwoaDay said: nooo thats worse than before Reveal hidden contents How is 12 worse than my guess of 6? Ive figured out there are at least 12...so if anything its better than my other guess!! Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 because you are wrong 6 is closer Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 tell me how there can be even 6 and i will be very surprised Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 27, 2008 Report Share Posted July 27, 2008 Reveal hidden contents These are the 12 combinations I have so far. Maybe I mis-read the question? If it has m before it its the man, if it doesn't its the women. I couldnt show the example in circles, so have put them in a line, same thing though - just imagine it in a circle! m4 3 m2 1 m3 4 m1 2 m4 3 m1 4 m2 1 m3 2 m4 3 m2 4 m1 2 m3 1 m4 3 m1 2 m3 4 m2 1 m4 2 m1 4 m3 1 m2 3 m4 2 m3 1 m2 4 m1 3 m4 2 m1 3 m2 4 m3 1 m4 2 m3 4 m1 3 m2 1 m4 1 m2 3 m1 4 m3 2 m4 1 m3 4 m1 3 m2 2 m4 1 m2 4 m3 2 m1 3 m4 1 m3 4 m1 2 m2 3 Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 27, 2008 Author Report Share Posted July 27, 2008 well it seems that you are right i was disagreeing because the book i got this from said there were only 2 i never really checked for more but i cant find anything wrong with your answers thank you for correcting the book, and good job Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 28, 2008 Author Report Share Posted July 28, 2008 ok, i finally realized why there are only two answers beacause this is a circular table, there is no first or last person. all of the variations posted other that the two are all just starting with different people, and yes i am pretty very sure about this. B)) :ph34r: Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 28, 2008 Report Share Posted July 28, 2008 TwoaDay said: ok, i finally realized why there are only two answers beacause this is a circular table, there is no first or last person. all of the variations posted other that the two are all just starting with different people, and yes i am pretty very sure about this. B)) :ph34r: If u imagine all my answers in circular form, there are 12 different variations. I don't understand what you are trying to say is wrong with it - can you be more specific? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted July 29, 2008 Report Share Posted July 29, 2008 Reveal hidden contents There are only two ways. Alternating with husband and wife opposite each other and beside each other. So my answer is 2. Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 29, 2008 Author Report Share Posted July 29, 2008 name='starfish' date='Jul 27 2008, 03:09 PM' post='53712'] These are the 12 combinations I have so far. Maybe I mis-read the question? If it has m before it its the man, if it doesn't its the women. I couldnt show the example in circles, so have put them in a line, same thing though - just imagine it in a circle! m4 w3 m2 w1 m3 w4 m1 w2 this m4 w3 m1 w4 m2 w1 m3 w2 this m4 w3 m2 w4 m1 w2 m3 w1 m4 w3 m1 w2 m3 w4 m2 w1 m4 w2 m1 w4 m3 w1 m2 w3 and this are the same m4 w2 m3 w1 m2 w4 m1 w3 and this are the same m4 w2 m1 w3 m2 w4 m3 w1 m4 w2 m3 w4 m1 w3 m2 w1 m4 w1 m2 w3 m1 w4 m3 w2 m4 w1 m3 w4 m1 w3 m2 w2 this doesent work m4 w1 m2 w4 m3 w2 m1 w3 m4 w1 m3 w4 m1 w2 m2 w3 this dosent work Quote Link to comment Share on other sites More sharing options...
0 TwoaDay Posted July 29, 2008 Author Report Share Posted July 29, 2008 im not sure about the rest, mabey someone else can help Quote Link to comment Share on other sites More sharing options...
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TwoaDay
Four couples enter a restaurant. How many ways can they be seated at a round table so that the men and women alternate and no husband and wife sit next to each other?
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