[Guest]

You enter a crazy new world and you are given a simple numercacy puzzle to live. You are told the following:

• 6+3=8
  
• 7+2=8
  
• 7*9=56
  
• 36/7=6
  

Your question is this:

What is (3+2)+(4x7)-(9-4)+(4-3)

BODMAS still applies

[Guest]

24

i think the second number in each operation is decreased by one.

btw, (4x7) means 4*7 ?

[Brandonb]

25

It looked to me like every even #'d odd number was decreased by one (1, 3, 5, 7, 9, 11, 13, 15). Or that every Prime number was decreased by one. Not enough info to tell which one it is for sure.

Edit: Or it could be rjsghk107's answer too, I hadn't considered that.

Edited July 22, 2008 by Brandonb

[Guest]

Brandonb...7*9=56...with your reasoning, it would be 6*9=56...but 6*9 is 54, so I doesn't appear that's the way it works. I got the same answer as rjsghk107 on this one, although it seems almost too simplistic.

[Brandonb]

Brandonb...7*9=56...with your reasoning, it would be 6*9=56...but 6*9 is 54, so I doesn't appear that's the way it works. I got the same answer as rjsghk107 on this one, although it seems almost too simplistic.

lol, oops! Thanks for catching that Well then yeah, I guess the other answer must be it.

[Guest]

I come up with 20

[Guest]

24 if you decrease the second value in each exp​ression 7*9=56 becomes 7*8=56 a valid exp​ression.

[Guest]

Following rjsghk107 thoughts, I see that the second number in the exp​ression is decreased by one but I would use that thought to substitute a 2 for a 3, a 1 for a 2, an 8 for a 9 and a 6 for a 7. This would result in the following equation:

(2+1)+(4x6)-(8-4)+(4-2)

which equals 25

[Guest]

btw, (4x7) means 4*7 ?

24

i think the second number in each operation is decreased by one.

yes 4x7 =4*7

[Guest]

24 if you decrease the second value in each exp​ression 7*9=56 becomes 7*8=56 a valid exp​ression.

24 is the correct answer. That was the easy one though..........

[Guest]

I come up with 20

I see my error now.

[Guest]

"I got 21 for an answer. Using the thought that the riddle is that the second operation is one number lower and keeping with BOMDAS

(3+2)+(4*7)-(9-4)+(4-3)

(4+24)-(6+2)

27-7

21"

[Guest]

24

[Guest]

do you continue to keep the applying the formula of reducing the second number of the problem all the way down as did thatguyfubu?

If so...

21

Edited July 22, 2008 by finance_it

[Guest]

The second number after the first operator need to be minus 1 before we carry out the calculation. If then

(3+2)+(4*7)-(9-4)+(4-3)

=(3+1)+(4*6)-(9-3)+(4-2)

=4+24-6+2

=(4+23)-(6-1)

=27-5

=27-4

=23 ?

and this is crazy.

[Guest]

8 + 20 - 0 + -1 = 27

You enter a crazy new world and you are given a simple numercacy puzzle to live. You are told the following:

• 6+3=8
  
• 7+2=8
  
• 7*9=56
  
• 36/7=6
  

Your question is this:

What is (3+2)+(4x7)-(9-4)+(4-3)

BODMAS still applies

[Guest]

Odd numbers are decrease by 1. Even numbers are left alone.

(2+2)+(4x6)-(8-4)+(4-2)=26

[Guest]

Odd numbers are decrease by 1. Even numbers are left alone.

(2+2)+(4x6)-(8-4)+(4-2)=26

6+3=8

7+2=8

7*9=56

36/7=6

this goes against the 3rd problem "7*9=56"

if odds were reduced then it would be "7*9=48"

[Guest]

You enter a crazy new world and you are given a simple numercacy puzzle to live. You are told the following:

• 6+3=8
  
• 7+2=8
  
• 7*9=56
  
• 36/7=6
  

Your question is this:

What is (3+2)+(4x7)-(9-4)+(4-3)

BODMAS still applies

anything after an operator is reduced by one so the answer would be...

(3+2)+(4*7)-(9-4)+(4-3)= (3+1)+(4*6)-(9-3)+(4-2)=

4+24-6+2= 4+23-5+1=

23

[Guest]

anything after an operator is reduced by one so the answer would be...

(3+2)+(4*7)-(9-4)+(4-3)= (3+1)+(4*6)-(9-3)+(4-2)=

4+24-6+2= 4+23-5+1=

23

Actually

I think the last integer per operation should be -1

(3+2)+(4*7)-(9-4)+(4-3)= (3+1)+(4*6)-(9-3)+(4-2)=

4+24-6+2= 4+23-6+1=

27-7= 27-6=

21

[Guest]

I would argue that even if someone tells you those four equations are correct, that doesn't mean they are. The key wording is, "You are told..." which allows for the following statement to be false. In that case I say:

5+28-5+1=29

As Lincoln put it, "How many legs does a dog have if you call the tail a leg? Four. Calling a tail a leg doesn't make it a leg. "

[Guest]

Actually

I think the last integer per operation should be -1

(3+2)+(4*7)-(9-4)+(4-3)= (3+1)+(4*6)-(9-3)+(4-2)=

4+24-6+2= 4+23-6+1=

27-7= 27-6=

21

I don't believe that there is any rule in BODMAS that says that you carry the () marks on throughout the problem.

(3+2)+(4*7)-(9-4)+(4-3)= (3+1)+(4*6)-(9-3)+(4-2)=

(4+24)-(6+2)= (4+23)-(6+1)=

(27-7)= (27-6)=

21

i think that you are inferring that there is [] around the first and second set like this

[(3+2)+(4*7)]-[(9-4)+(4-3)]

and if that were the case then i would agree with 21

but that is not how i read the original problem

hopefully one of us is close to correct and timbolina will provide us with a correct answer and the reasoning for it

[Guest]

You enter a crazy new world and you are given a simple numercacy puzzle to live. You are told the following:

• 6+3=8
  
• 7+2=8
  
• 7*9=56
  
• 36/7=6
  

Your question is this:

What is (3+2)+(4x7)-(9-4)+(4-3)

BODMAS still applies

24

[Guest]

You enter a crazy new world and you are given a simple numercacy puzzle to live. You are told the following:

• 6+3=8
  
• 7+2=8
  
• 7*9=56
  
• 36/7=6
  

Your question is this:

What is (3+2)+(4x7)-(9-4)+(4-3)

BODMAS still applies

(3+2)=5 (4x7)=28 <<if this is first part of sum then answer would be 5+27=32

(9-4)=5 (4-3)=1 <if this is second part of sum then answer would be 5+0=5

that means 32-5=27

or 32-4=28

or if first two sums are first part etc it would be :-

33-6=27 or in a strange world 33-5=28