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Ok, this one is (hopefully) a little harder than my first two:

11,13,12,13,12,11,11,X?

What comes next, and why?

I may post a hint if the post seems to be lingering... ;)

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Ok, this one is (hopefully) a little harder than my first two:

11,13,12,13,12,11,11,X?

What comes next, and why?

I may post a hint if the post seems to be lingering... ;)

14. It just follows the logica progression. 11 to 13 establishes the range. Then, you work from the midpoint upward (12 to 13). Work from the midpoint downward (12 to 11). Return to the starting point: 11. Establish the next range by adding 1, therefore: 14.

G Brown

Dallas

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14. It just follows the logica progression. 11 to 13 establishes the range. Then, you work from the midpoint upward (12 to 13). Work from the midpoint downward (12 to 11). Return to the starting point: 11. Establish the next range by adding 1, therefore: 14.

G Brown

Dallas

Oh, I might ammend this by saying I am assuming you are consistently headed in an increasing numerical direction. Also, IF you are only working with whole numbers (that info is not provided), you have to go to 15, not 14.

PS: If this is supposed to just simply be an endless loop, then you have to go back to 13... and the same sequence starts all over again.

Edited by gbrown
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Welcome to the Den G Brown!

Please have a look at using Spoilers so that other can continue to work on the problem at the same time. While I like the creativeness of your solution, it is not correct.

I will say at this point, the question only deals with whole numbers, and is a finite series. :)

Edited by Jarod997
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Welcome to the Den G Brown!

Please have a look at using Spoilers so that other can continue to work on the problem at the same time. While I like the creativeness of your solution, it is not correct.

I will say at this point, the question only deals with whole numbers, and is a finite series. :)

Ooops. Advice well taken. Thank you.

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for each set of ones add them to get the number they represent except for the last set because they will follow with something else. that gives: 33121312.

To make it so that it reads the same frontwards and backwards, the end has to be 133. How to do that with the last ones and a next number? One could add another 9 ones and a 3 (11,11,11,11,13).

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15. Considered as sums of pairs which follow a patterned sequence based on the total of the first pair, we see this emerge: the first pair total 24; the second ascends by 1, 25; the third descends by 1, 23 and if the fourth is to ascend by two, then the other digit with 11 must be 15, totaling 26.

However, does this sequence which can continue to expand in both directions violate the "finite" aspect of the puzzle?

Ok, this one is (hopefully) a little harder than my first two:

11,13,12,13,12,11,11,X?

What comes next, and why?

I may post a hint if the post seems to be lingering... ;)

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G Brown: again, a creative solution but it would violate being a finite series.

Here is a hint to get everyone thinking a bit more:

"Canadianized" version of the sequence: 10,11,8,7,8,6,9,10,Y?

Bonus points if you can get the correct values for both X and Y. Good luck!

Edited by Jarod997
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Ok, ok, I'll give you not so much a hint, but a direction to steer you in.

This puzzle has less to do with math and more to do with something else.

Spoiler for A Little More:

See my hint I posted above... it is significant.
Edited by Jarod997
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Ok, ok, I'll give you not so much a hint, but a direction to steer you in.

This puzzle has less to do with math and more to do with something else.

Spoiler for A Little More:

See my hint I posted above... it is significant.

10. Series +2, -1, +1, -1, 0, -1.... next number is 11-1 = 10

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Welcome to the Den jetagent!

Please look at using Spoilers as other people may want to work on the puzzle at the same time.

While I admire your logic, that is not the answer I am looking for. Would that same logic work with the hint I posted above? :)

Edited by Jarod997
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Yes, it is 12! But you forgot to tell me why...

And the bonus question, what is the value for Y in the Canadianized version? (See previous hint)

Edited by Jarod997
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