Jump to content
BrainDen.com - Brain Teasers
  • 0
Sign in to follow this  
FUZZY

alphametic puzzle

Question

substitute distinct numbers for each letter

 

ADDITION PROBLEM

 

             
        C A S E
        C O P S
      C L O S E
    C O R P S E
    C O L L A R
    C E L L A R
               
               
    R E C T O R

how to solve?

 

             

Share this post


Link to post
Share on other sites

4 answers to this question

  • 0
Spoiler

A=1 C=2 E=4 L=9 O=7 P=3 R=8 S=0 T=6

2104 + 2730 + 29704 + 278304 + 279918 + 249918 = 842678

 

Share this post


Link to post
Share on other sites
  • 0

To begin with, C must be less than 4, otherwise the sum would have 7 digits. If C is 3, then R is 9 and C+O+O+E < E, which is impossible, so C cannot be 3. This leaves only two options for C (either 1 or 2). If you try C=1 with various values for O, you can prove that C cannot be 1. Repeat with C=2 to find the solution.

Share this post


Link to post
Share on other sites
  • 0

 So you have to assume  c=1 and try 2 to 9 for O? If it is deduced that c=2, then again try all other values for O?

isn't there a shorter and more efficient way of solving?

 

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

Sign in to follow this  

  • Recently Browsing   0 members

    No registered users viewing this page.

×