JensArpe Posted May 21, 2014 Report Share Posted May 21, 2014 Hey everybody, can you solve this riddle? seems easy at first, but actually.. it isn't! Quote Link to comment Share on other sites More sharing options...
0 Rainman Posted May 21, 2014 Report Share Posted May 21, 2014 Count modulo 3. All numbers are congruent with 0, except 19 and 25 which are congruent with 1. 50 is congruent with 2, so any solution must use both 19 and 25. 19+25 = 44, so only 6 remains. The unique solution is to leave buckets 6, 19, and 25. Quote Link to comment Share on other sites More sharing options...
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JensArpe
Hey everybody,
can you solve this riddle?
seems easy at first, but actually.. it isn't!
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