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Can you solve this?


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Count modulo 3. All numbers are congruent with 0, except 19 and 25 which are congruent with 1. 50 is congruent with 2, so any solution must use both 19 and 25. 19+25 = 44, so only 6 remains. The unique solution is to leave buckets 6, 19, and 25.

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