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bonanova
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A wizard selects three excellent logicians and places hats on their heads.

He explains to them he has written a positive integer on each hat, and

that one of the numbers is the sum of the other two. Each logician can

see only the numbers on the other two hats.

A prize is offered to the first person able to be certain of the number on

his own hat. The wizard starts questioning the logicians in order, starting

over again if none of them can be certain of his number.

There is no guessing.

Each logician must answer: "My number is ___" or "I don't know."

[1] Can any of the logicians win the prize?

[2] If so, which one?

[3] How many rounds of questions will it take?

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you know your #is prime and if you add the other 2 #s together and its a prime # it might be yours but if its not then you know your # pluss the person with the lowest # should = the highest persons #

but

if you are the person with the highest # and you add the other two # together you should get your # but to be sertan that your answer is corect you - the lowest # YOU SEE by the highest you see if its a prime # that is most likely your #

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you know your #is prime and if you add the other 2 #s together and its a prime # it might be yours but if its not then you know your # pluss the person with the lowest # should = the highest persons #

but

if you are the person with the highest # and you add the other two # together you should get your # but to be sertan that your answer is corect you - the lowest # YOU SEE by the highest you see if its a prime # that is most likely your #

... completely lost me

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sorry

don't be sorry! i'm just saying I'm trying to understand what you mean. Is there another way you could explain it? Or is it pretty much as simple as it gets in your explanation?

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you know you are a prime #

when you add a+b together and it its a prime # that might be your # if its not a prime # it cant be your #

if thats not your # then subtract a-b (if a is bigger) if the answer to that is prime it might be your #

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