phil1882 Posted August 12, 2013 Report Share Posted August 12, 2013 consider the golden ratio. 1.618.... now, imagine multiplying this by each integer. keep the numbers it truncates to. 1 1.618*2 = 3 1.618*3 = 4 1.618*4 = 6 1.618*5 = 8 1.618*6 = 9 and so on. its a very interesting sequence with some "nice" properties. now here's my question. if you're allowed any irrational number; which one goes through the most primes and fewest composites? Quote Link to comment Share on other sites More sharing options...
0 DeGe Posted August 12, 2013 Report Share Posted August 12, 2013 Prime numbers (greater than 3) are of the form 6n+1 or 6n-1 Since approximating 6n+1 using a rational number will be difficult as n increases, lets consider only 6n-1 cases. As we are rounding down the numbers, an expression close to but only just less than 6 that gives all the numbers of form 6n-1, will have almost a third of the numbers prime. Therefore using 5.99999999... we would get all 6n-1 numbers and nearly 1/3 of these numbers would be prime Quote Link to comment Share on other sites More sharing options...
0 Anza Power Posted August 13, 2013 Report Share Posted August 13, 2013 ^ 5.999999... (continue forever) is actually 6.And if it doesn't continue forever then at some point you will get 6n-2... Quote Link to comment Share on other sites More sharing options...
Question
phil1882
consider the golden ratio.
1.618....
now, imagine multiplying this by each integer. keep the numbers it truncates to.
1
1.618*2 = 3
1.618*3 = 4
1.618*4 = 6
1.618*5 = 8
1.618*6 = 9
and so on.
its a very interesting sequence with some "nice" properties.
now here's my question. if you're allowed any irrational number;
which one goes through the most primes and fewest composites?
Link to comment
Share on other sites
2 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.