Guest Posted November 20, 2011 Report Share Posted November 20, 2011 x by mistake dropped his two watches in the water.As a result one clock is gaining 2 seconds in each hr while other is losing 2.5 seconds an hour.Now, if their watches show the same time,how long will it be before they show the same time again. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 20, 2011 Report Share Posted November 20, 2011 This sounds more like a homework problem than a logic puzzle. The solution is simple:HINT]recognize the differential time between watches has greater significance than differential between each watch and real time.I hope the hint gives you sufficient to see the solution method but I won't give you the answer. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 20, 2011 Report Share Posted November 20, 2011 We could make this a little more interesting so I will suggest a part B: Assume that this occurred at noon today 11/20/2011. Give date and time that the two watches once again are coordinated. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 22, 2011 Report Share Posted November 22, 2011 I agree this sounds more like a homework problem but it doesn't look like they're coming back. Interesting results with my stab at it 4.5 seconds/hour would take 400 days to have the total of the watches change by 12 hours. Coincidentally I'll be wearing my santa hat next year and having a nice midday lunch when that occurs. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 23, 2011 Report Share Posted November 23, 2011 I agree this sounds more like a homework problem but it doesn't look like they're coming back. Interesting results with my stab at it 4.5 seconds/hour would take 400 days to have the total of the watches change by 12 hours. Coincidentally I'll be wearing my santa hat next year and having a nice midday lunch when that occurs. Your answer of noon and 400 days is correctAssuming you wear your Santa's hat on 12/25/2012, Christmas day, then your date is in error!is the fact that 2012 is a leap year, hence 366 days long. Quote Link to comment Share on other sites More sharing options...
0 Morningstar Posted November 23, 2011 Report Share Posted November 23, 2011 (edited) Your answer of noon and 400 days is correctAssuming you wear your Santa's hat on 12/25/2012, Christmas day, then your date is in error!is the fact that 2012 is a leap year, hence 366 days long. Pity...it would have been an interesting coincidence. Edited November 23, 2011 by Morningstar Quote Link to comment Share on other sites More sharing options...
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x by mistake dropped his two watches in the water.As a result one clock is gaining 2 seconds in each hr while other is losing 2.5 seconds an hour.Now, if their watches show the same time,how long will it be before they show the same time again.
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