Guest Posted October 22, 2011 Report Share Posted October 22, 2011 Triangular ABC and O point inside it, has given. Find E point on AB side, D point on BC side and F point on AC side, so that sum EO+OD+DF+FE reaches its minimum. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 22, 2011 Report Share Posted October 22, 2011 Points e and f coinciding with a. d be the base of perpendicular from a. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 23, 2011 Report Share Posted October 23, 2011 Points e and f coinciding with a. d be the base of perpendicular from a. no random guess. need proof. answer is wrong btw Quote Link to comment Share on other sites More sharing options...
0 hhh3 Posted October 24, 2011 Report Share Posted October 24, 2011 let points E,D,&F be at middle of AB, BC & AC.... and O anywhere in line joining E&D not good in geomtry but anyway..... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 24, 2011 Report Share Posted October 24, 2011 E,F and D are the foot of the perpiduculars from point O. which guarantees that OE,OF,OD are minimum. Also FE will then be less(This will though depend on location of point O). So i think for this situation the overall sum will be minimum. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 24, 2011 Report Share Posted October 24, 2011 E as B D as C F as A Proof: Max distance can be edges only.... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 25, 2011 Report Share Posted October 25, 2011 Incomplete proof but answer and a beginning:To determine shortest, break up the problem. Given O and F, to minimize FE+EO, the acute angle between FE and AB must equal the acute angle between AB and EO. Similarly, to minimize OD+DF, the acute angle between OD and BC must equal the acute angle between BC and DF. Position of F should be the point on AC from which a perpendicular passes through point O. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 2, 2011 Report Share Posted November 2, 2011 Incomplete proof but answer and a beginning:To determine shortest, break up the problem. Given O and F, to minimize FE+EO, the acute angle between FE and AB must equal the acute angle between AB and EO. Similarly, to minimize OD+DF, the acute angle between OD and BC must equal the acute angle between BC and DF. Position of F should be the point on AC from which a perpendicular passes through point O. Your on the right track. I highlighted wrong statements. And how could you find E point so that the acute angle between FE and AB equals the acute angle between AB and EO. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 2, 2011 Report Share Posted November 2, 2011 E as B D as C F as A Proof: Max distance can be edges only.... Its not true Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 7, 2011 Report Share Posted November 7, 2011 use symmetry Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 7, 2011 Report Share Posted November 7, 2011 Setting up your triangle so AC is your base the line FO would be perpendicular to AC and OD and OE are both parrallel to AC. Not sure how to prove it though. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 17, 2011 Report Share Posted November 17, 2011 Setting up your triangle so AC is your base the line FO would be perpendicular to AC and OD and OE are both parrallel to AC. Not sure how to prove it though. u can't prove it becouse its wrong. Quote Link to comment Share on other sites More sharing options...
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Triangular ABC and O point inside it, has given. Find E point on AB side, D point on BC side and F point on AC side, so that sum EO+OD+DF+FE reaches its minimum.
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