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E,F and D are the foot of the perpiduculars from point O.

which guarantees that OE,OF,OD are minimum.

Also FE will then be less(This will though depend on location of point O).

So i think for this situation the overall sum will be minimum.

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Incomplete proof but answer and a beginning:

To determine shortest, break up the problem. Given O and F, to minimize FE+EO, the acute angle between FE and AB must equal the acute angle between AB and EO. Similarly, to minimize OD+DF, the acute angle between OD and BC must equal the acute angle between BC and DF. Position of F should be the point on AC from which a perpendicular passes through point O.

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Incomplete proof but answer and a beginning:

To determine shortest, break up the problem. Given O and F, to minimize FE+EO, the acute angle between FE and AB must equal the acute angle between AB and EO. Similarly, to minimize OD+DF, the acute angle between OD and BC must equal the acute angle between BC and DF. Position of F should be the point on AC from which a perpendicular passes through point O.

Your on the right track. I highlighted wrong statements. And how could you find E point so that the acute angle between FE and AB equals the acute angle between AB and EO.

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Setting up your triangle so AC is your base the line FO would be perpendicular to AC and OD and OE are both parrallel to AC. Not sure how to prove it though.

u can't prove it becouse its wrong.

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