[wolfgang]

Three pairs(3 men and their 3 wives)wanted to cross a river using a boat which can carry maximally 2 persons.

they should use this boat to cross the river, and there is no other boat.

Each pair concider the other pairs as strangers and regards them as enemies.

If :

strength of any man alone is 70.

strength of any woman alone is 10.

the strength of any pair is 40.

so ...if any man(when his wife is not with him) on any side of the river, come in contact with any pair,he will kill them.but he can not attack two pairs( 40+40= 80....80>70).

he can also attack any woman(other than his wife)if she is alone with him .

The same is true if two men (without their wives) can attack any pair.

The pair can not attack any one.

Two men alone on any side will not attack each other.

women will not attack at all.

how can they cross the river safely?

[Guest]

If a man is in the boat alone, and reaches a side with a pair to let another man in the boat, will the first man stay in the boat or kill the pair?

And alternatively, if a pair is in a boat and a man on shore, will the man on shore kill the pair in the boat, or only kill them if they both come ashore?

Edited June 16, 2011 by Nana7

[Guest]

Lets call the couples A, B, and C

Man A goes across the river with man B. Man A leaves Man B there and returns. Man A then brings Man C over to Man B and leaves him there; Man A returns. Lady B takes Lady C over to her husband and Man B and Lady B return. Man and Lady A go to the side with the C couple where Lady A is dropped off. Man A returns. Man B takes Lady B over and returns. Finally, Man A and B return to the far side.

This is assuming Man A doesn't come out and kill Lady B and Couple C after coming back from dropping off Man B.

Edited June 16, 2011 by harpuzzler

[Guest]

Lets call the couples A, B, and C

Man A goes across the river with man B. Man A leaves Man B there and returns. Man A then brings Man C over to Man B and leaves him there; Man A returns. Lady B takes Lady C over to her husband and Man B and Lady B return. Man and Lady A go to the side with the C couple where Lady A is dropped off. Man A returns. Man B takes Lady B over and returns. Finally, Man A and B return to the far side.

This is assuming Man A doesn't come out and kill Lady B and Couple C after coming back from dropping off Man B.

Near the end of your suggested solution, where Man A returns after dropping off Lady A, he returns to find Couple B standing alone and kills them.

[Guest]

Couple A goes across. Lady A returns. Men B and C go across. Man A returns. Ladies B and C go across. Couple B returns. Ladies A and B go across. Now with all ladies being across, Man C can return and bring Man B, then return again and bring Man A.

[Guest]

1. 
   
2. [P,P,.] -> [.,.,P] A pair travels to the other side.
   
3. [P,P,W] <- [.,.,M] The woman returns with the boat.
   
4. [W,W,W] -> [M,M,M] Men from remaining pairs travel to the other side.
   
5. [W,W,P] <- [M,M,.] One of the men returns with the boat.
   
6. [.,.,P] -> [P,P,.] The man stays with his wife, while the other two women move to the other side.
   
7. [.,P,P] <- [P,.,.] A pair returns with the boat.
   
8. [.,M,M] -> [P,W,W] The two women travel to the other side.
   
9. [M,M,M] <- [W,W,W] The remaining men on the other side returns with the boat.
   
10. [.,.,M] -> [P,P,W] Two of the three men travel to the other side.
    
11. [.,M,M] <- [P,W,W] One man returns with the boat.
    
12. [.,.,.] -> [P,P,P] Last two man travel to the other side.
    

Edited June 17, 2011 by KlueMaster

[Guest]

Let the pairs be named as 1,2 and 3. So the husband and wifes would be H1, W1 and so on. With this Let W1 and H1 go to the other side first. W1 will come back and then W1 and W2 go through.. After this W2 would come back.. Then W2 and W3 would go and H1 would come back. Now H1 and H2 would come. Leaving H2 at other side, H1 would go back to take H3 and come back together and everyone would have crossed.

And i also believe there may be other ways..

[Guest]

Let the pairs be named as 1,2 and 3. So the husband and wifes would be H1, W1 and so on. With this Let W1 and H1 go to the other side first. W1 will come back and then W1 and W2 go through.. After this W2 would come back.. Then W2 and W3 would go and H1 would come back. Now H1 and H2 would come. Leaving H2 at other side, H1 would go back to take H3 and come back together and everyone would have crossed.

And i also believe there may be other ways..

That's where M2 will be alone with the third pair.

[wolfgang]

Lets call the couples A, B, and C

Man A goes across the river with man B. Man A leaves Man B there and returns. Man A then brings Man C over to Man B and leaves him there; Man A returns. Lady B takes Lady C over to her husband and Man B and Lady B return. Man and Lady A go to the side with the C couple where Lady A is dropped off. Man A returns. Man B takes Lady B over and returns. Finally, Man A and B return to the far side.

This is assuming Man A doesn't come out and kill Lady B and Couple C after coming back from dropping off Man B.

he`ll do it...when man A returns to other side where the pair B are alone...he`ll kill them.

[wolfgang]

Couple A goes across. Lady A returns. Men B and C go across. Man A returns. Ladies B and C go across. Couple B returns. Ladies A and B go across. Now with all ladies being across, Man C can return and bring Man B, then return again and bring Man A.

very good...

[wolfgang]

Let the pairs be named as 1,2 and 3. So the husband and wifes would be H1, W1 and so on. With this Let W1 and H1 go to the other side first. W1 will come back and then W1 and W2 go through.. After this W2 would come back.. Then W2 and W3 would go and H1 would come back. Now H1 and H2 would come. Leaving H2 at other side, H1 would go back to take H3 and come back together and everyone would have crossed.

And i also believe there may be other ways..

when W1 and W2 go through..H2 will kill pair 3.

Edited June 17, 2011 by wolfgang

[Guest]

when W1 and W2 go through..H2 will kill pair 3.

Yup i'm sorry. Didn't realize that.

[Guest]

Lets say pairs are H1W1 (husband, wife), H2w2 and H3W3

Now:

H1H2 -> H1 comes back

H1H3 -> H1 comes back

W2W3 -> H2W2 comes back

W2W1 -> H3 comes back

H1H2 -> W3 comes back

H3W3 ->

[wolfgang]

Lets say pairs are H1W1 (husband, wife), H2w2 and H3W3

Now:

H1H2 -> H1 comes back

H1H3 -> H1 comes back

W2W3 -> H2W2 comes back

W2W1 -> H3 comes back

H1H2 -> W3 comes back

H3W3 ->

good! but you are not the first...lol

[Hidden G]

hello everyone there's a similar game here,and there's another one like the one posted by WolfGang on facebook the same but i played it like 2 years ago ,it's interesting and that genius IQ solve it in about 10 minutes,u should search in IQ games .

[Hidden G]

BTW found 2 other,the first will have some japanese language (it doesn't matter just click the red button first and everything will be good)

and for culture :This is an IQ test given to job applicants in Japan.

the second is another one with different characters .