Guest Posted November 16, 2010 Report Share Posted November 16, 2010 (edited) Ok everyone! Without picking at wikipedia or anywhere else, can you prove that any number under the power of zero equals to 1? x0 = 1 Edited November 16, 2010 by Tsopi Quote Link to comment Share on other sites More sharing options...
0 k-man Posted November 16, 2010 Report Share Posted November 16, 2010 x0 = xn-n = xn / xn = 1 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 16, 2010 Report Share Posted November 16, 2010 this assumes we've established that x ^ (y-z) = x^y/x^z let y=z, then x^(y-z) = x^(y-y) = x^0 x^(y-z) = x^y/x^z = x^y/x^y = 1 therefore x^0 =1 sloppy but... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 16, 2010 Report Share Posted November 16, 2010 aww man, k-man beat me...you're lucky you're on the EDT Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 16, 2010 Report Share Posted November 16, 2010 My understanding is that the x0 = 1 by definition. One often sees proofs based on the law of exponents (as above), but I haven't seen a proof of the law of exponents that didn't implicitly assume that a x0 = 1. Quote Link to comment Share on other sites More sharing options...
0 Akriti Posted November 16, 2010 Report Share Posted November 16, 2010 xa-a=xa/xa=1 Hence proved. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 16, 2010 Report Share Posted November 16, 2010 Ok everyone! Without picking at wikipedia or anywhere else, can you prove that any number under the power of zero equals to 1? x0 = 1 x^(a-a) = x^a / x^a = 1 Quote Link to comment Share on other sites More sharing options...
0 k-man Posted November 16, 2010 Report Share Posted November 16, 2010 aww man, k-man beat me...you're lucky you're on the EDT How does it help me being on EDT? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 16, 2010 Report Share Posted November 16, 2010 the joke was funnier in my head...basically it was 8:51 am for you before it was for me (or for you it was 9:51 am for you before it was for me) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 17, 2010 Report Share Posted November 17, 2010 I prove this to my middle schoolers through a simple explanation using the chart below 3^1 3^2 3^3 3^4 3^5 3 9 27 81 243 As we go to the right, the values are multiplied by 3, and the exponents go up by one. Following a similar pattern, as we go to the left, the values are divided by 3, and the exponents go down by one. When you get to 3^1, and you continue the chart, you get 3/3 is 1, and the exponent goes down one to zero. This can be continued to show how negative exponents give smaller numbers and place values as well. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 18, 2010 Report Share Posted November 18, 2010 (edited) Heyyyy its still not solved yet guys, for unfortunately , your answer z not general because u stated X0=Xn-n=Xn/Xn=1 (((( but the question still why 00=1 and the prev sloving is not workin for this case because we cannot divide by X0=0 ))) so let's think why this case is also 0^0=1 ^^)) Edited November 18, 2010 by dibasoufiane Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 18, 2010 Report Share Posted November 18, 2010 (edited) nm Edited November 18, 2010 by maurice Quote Link to comment Share on other sites More sharing options...
Question
Guest
Ok everyone!
Without picking at wikipedia or anywhere else, can you prove that any number under the power of zero equals to 1?
x0 = 1
Edited by TsopiLink to comment
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