[Guest]

As far as I know this one has a unique solution.. let's see if I am wrong:

By using the numbers 1, 3, 4, and 6, with any mathematical operation +, −, ×, and ÷, brackets, make the number 24. Each number must be used once and only once. Decimal points are not allowed at any place. Mathematical operations can be used any number of times..

[Guest]

6 / ( 1 - 3/4 ) = 24

[Guest]

a

Edited June 17, 2010 by Goku

[Guest]

Could find 2 solutions

1. 6/(1-3/4)

2. {(6!/4!)-3!}*1

Edited June 17, 2010 by Goku

[Guest]

1³(6x4)=24

Edited June 17, 2010 by YODI

[unreality]

three different solutions have already been found above me (although only Hugo's follows the official rules) but here's a fourth:

1 * 4_C_3 * 6 = 24

where nCr is combination, ie, "n choose r" or n! / (r! (n-r)!)

therefore 4_C_3 = 4! / (3! 1!) = 4! / 3! = 4

if I had a piece of paper I could write it without the c, it's just a parentheses with numbers on top of the other, it's quite common. Therefore it would follow the rules of the OP of just parentheses and numbers and the basic four operators

[Guest]

6-4=2, combine the 2 and 3 to make 23, add 1 to get 24. This only works if I can combine the 2 and 3....

[Guest]

6/(1-3/4)