Guest Posted April 9, 2010 Report Share Posted April 9, 2010 (edited) A and B are any two roots of the quartic equation: x4 + x3 - 1 = 0. Prove that A*B is always a root of the equation: x6 + x4 + x3 - x2 - 1 = 0. *** For an extra challenge, solve this problem without the aid of a computer program or online equation solver. Edited April 9, 2010 by K Sengupta Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2010 Report Share Posted April 9, 2010 The quartic equation only has two real roots. Quote Link to comment Share on other sites More sharing options...
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A and B are any two roots of the quartic equation: x4 + x3 - 1 = 0.
Prove that A*B is always a root of the equation: x6 + x4 + x3 - x2 - 1 = 0.
*** For an extra challenge, solve this problem without the aid of a computer program or online equation solver.
Edited by K SenguptaLink to comment
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