Jump to content
BrainDen.com - Brain Teasers
  • 0


Guest
 Share

Question

Janice writes a sequence of integers starting with the number 12. Each subsequent

integer she writes is chosen randomly with equal probability from amongst the positive divisors of the previous integer (including the possibility of the integer itself). She keeps writing integers until she writes the integer 1 for the first time, and then she stops.

An example of one such sequence is 12, 6, 6, 3, 3, 3, 1.

What is the expected value of the number of terms in Janice’s sequence?

Link to comment
Share on other sites

2 answers to this question

Recommended Posts

  • 0

Lets call the expected number of items following the number n, E(n).

E(1) = 0

E(2) = 1 + 0.5*[E(1) + E(2)] = 2

E(3) = 1 + 0.5*[E(1) + E(3)] = 2

E(4) = 1 + 0.33*[E(1) + E(2) + E(4)] = 2.5

E(6) = 1 + 0.25*[E(1) + E(2) + E(3) + E(6)] = 2.67

E(12) = 1 + 0.167*[E(1) + E(2) + E(3) + E(4) + E(6) + E(12)] = 3.033

And the 12 itself gives 4.033... or 121/30

unreality - looks like you've approximated that using a program, buts its very close :).

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Answer this question...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

Loading...
 Share

  • Recently Browsing   0 members

    • No registered users viewing this page.
×
×
  • Create New...