Well, I made up this problem. So if you need any clarification, just ask. I would be glad to explain.
You are given 3 dice. One dice is normal unbiased, one dice is biased for even numbers and the third is biased for odd number.
Biased for even(odd) numbers means that when the dice is rolled, the probability that the number facing up will be even(odd) is 4/5. Also, each of the even(odd) numbers have equal probability of being on top and so do the odd(even).
That is, if you roll the dice biased for even numbers, the probability of having 2 on top is 4/5 x 1/3 = 4/15, while the probability of having 1 on top is 1/5*1/3 = 1/15
In the unbiased dice, each number (1 to 6) has equal probability of being on the top face.
The three dice are rolled together over and over, and their sum (of numbers on the top faces of the three dice) "S" noted each time.
What value of "S" is expected to be most frequent?
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Well, I made up this problem. So if you need any clarification, just ask. I would be glad to explain.
You are given 3 dice. One dice is normal unbiased, one dice is biased for even numbers and the third is biased for odd number.
Biased for even(odd) numbers means that when the dice is rolled, the probability that the number facing up will be even(odd) is 4/5. Also, each of the even(odd) numbers have equal probability of being on top and so do the odd(even).
That is, if you roll the dice biased for even numbers, the probability of having 2 on top is 4/5 x 1/3 = 4/15, while the probability of having 1 on top is 1/5*1/3 = 1/15
In the unbiased dice, each number (1 to 6) has equal probability of being on the top face.
The three dice are rolled together over and over, and their sum (of numbers on the top faces of the three dice) "S" noted each time.
What value of "S" is expected to be most frequent?
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