BMAD

In other words, the judges agree that a defendant should be liable only if P and Q are both true.

The accused is brought forth in front of the tribunal. The three judges must hear the accusations and the defense to make a determination of innocent or guilt. In this particular case, the accused is found guilty ( C ) if the action in question is defined as illegal (P) and the accused committed the action (Q) or in other words . Judge number 1 found both P and Q true, Judge number 2 found only Q true, and Judge number 3 found only P true. Should the accused be found guilty?

I am sorry but this isn't correct.

i am too :-)

nope

This question comes from a modified white elephant gift exchange game (and is a tip of the hat to the many swapping puzzles out there lately). This version of 'White Elephant' is rather simple: There are six gifts and five people. Each gift is a check worth either $1,$10, $100, $1,000, $10,000, and $100,000. No one knows which check is which as they are hidden in sealed envelopes. One person gets to select first. They open the gift and reveal the prize to the group. The person who goes second has a choice, they can take the gift from the first person or select another mystery envelope. If they select a new envelope, then like the first person they reveal the gift to the group and allow the next person an option to take any gift previously opened or open a new envelope. If a person elects to take an opened envelope from a previous person then that item is now permanently theirs and no one can take it from them. The person who lost their envelope now must select a new envelope from the unopened pile. Each person continues until they have an envelope (with one envelope left unopened). The order of selecting the gifts must be finalized before any picking starts. What would be the best position to go in if you get to decide when you pick? What would be your expected winnings? **Thank you for catching that

This question comes from a modified white elephant gift exchange game (and is a tip of the hat to the many swapping puzzles out there lately). This version of 'White Elephant' is rather simple: There are six gifts and five people. Each gift is a check worth either $10, $100, $1,000, $10,000, and $100,000. No one knows which check is which as they are hidden in sealed envelopes. One person gets to select first. They open the gift and reveal the prize to the group. The person who goes second has a choice, they can take the gift from the first person or select another mystery envelope. If they select a new envelope, then like the first person they reveal the gift to the group and allow the next person an option to take any gift previously opened or open a new envelope. If a person elects to take an opened envelope from a previous person then that item is now permanently theirs and no one can take it from them. The person who lost their envelope now must select a new envelope from the unopened pile. Each person continues until they have an envelope (with one envelope left unopened). The order of selecting the gifts must be finalized before any picking starts. What would be the best position to go in if you get to decide when you pick? What would be your expected winnings?

Sorry nana but this is incorrect.

nope.

yes. Number 7 is empty.

Each circle has 1 and only one rule and each circle has at least 1 shape. But only the circle must have a shape not every subsection of the circles.

The rules may contradict each other. One circle could be pentagons only and another circle be squares only and therefore would have nothing in their share space.

Two similar triangles with integral sides have two of their sides the same. If the third sides differ by 20141, find all of the sides.

A car travels downhill at 72 mph (miles per hour), on the level at 63 mph, and uphill at only 56 mph The car takes 4 hours to travel from town A to town B. The return trip takes 4 hours and 40 minutes. Find the distance between the two towns.

The derivative of x2, with respect to x, is 2x. However, suppose we write x2 as the sum of x x's, and then take the derivative: Let f(x) = x + x + ... + x (x times) Then f'(x) = d/dx[x + x + ... + x] (x times) = d/dx[x] + d/dx[x] + ... + d/dx[x] (x times) = 1 + 1 + ... + 1 (x times) = x This argument appears to show that the derivative of x2, with respect to x, is actually x. Where is the fallacy?

Would it be easier to find the 1:1 lie:truth teller or the 4:1 lie:truth teller?

nope

nope