ac = 2
ad + bc = 3
bd = -2
c - a = -1
d - b = 3
d = 3 + b
b(3+b) = -2
b2+3b+2 = 0
(b+2)(b+1) = 0, b = -2 and d = 1 or b =-1 and d=2
c - a = -1
c = -1 + a
ac = 2
a(-1+a)=2
a2-a-2=0
(a-2)(a+1)=0; a=2 and c =1 or a=-1 and c=-2
b = -2 and d = 1 or b =-1 and d=2
a=2 and c =1 or a=-1 and c=-2
ad = 4 or 2 or -1 or -2
bc = -2 or 4 or -1 or 2
given:
ad + bc = 3
ad = 4 when bc = -1 so a = 2, d = 2, b = -1, c = 1
ad= -1 when bc = 4 so a = -1, d = 1, b = -2, c = -2
there are two answers