curr3nt
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Everything posted by curr3nt
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Situation........Your argument.........My counter If not observed, and no sound is made, the tree never fell. - agreed If not observed, and sound is made, the tree fell. - the tree falling can not be proven, the sound could have come from something else If observed, and sound is made, the tree fell. - agreed This is the essence of the question. To know the tree fell it would have to be observed. This contradicts the question when it says no one was around to hear it. edit - bonanova said it better
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@Molly Mae - But if the sound was not heard then the falling was not seen. How can you argue the sound without perception without questioning the event without the same perception?
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If you can't prove the sound exists because no one was there to hear it then how can you prove the tree fell in the first place?
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Eliminating sets to 113 to test is better than just plugging in numbers. 44 possible values in each variable 44 * 44 * 44 = 85184 sets. Makes the trial and error approach more managable.
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Let x = 1989 - c^2 c = 26 then x = 1313 ... c = 44 then x = 53 Using a^2 + b^2 = x and a <= b <= c We can limit the range of b for each x. sqrt(x/2) <= b <= sqrt(x) { replace sqrt(x) with c if sqrt(x) > c since b <= c } So for the 19 cases of c, I come up with 113 possible values of b and c for trial and error. Examples: (The first comparison is a < not a <= because sqrt(x/2) is not an integer for any of the values of c) c = 26 => 25 < b <= 26(36) { replaced with c } => 1 possible value c = 31 => 22 < b <= 31(32) { replaced with c } => 9 possible values c = 32 => 21 < b <= 31 => 10 possible values c = 33 => 21 < b <= 30 => 9 possible values c = 44 => 5 < b <= 7 => 2 possible values
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For uniqueness lets say: a <= b <= c We know the largest value c could be is 44. Because the square root of 1989 is ~= 44. We can determine a lowest value using the same value for each variable. c^2 + c^2 + c^2 = 1989 => 3c^2 = 1989 => c^2 = 663 => c ~= 25 So 25 < c <=44 for each set that could exist. This cuts down on trial and error attempts. edit - changed 25 <= c to 25 < c
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Wrote a quick program and found 11 unique sets. edit - Interesting that only one number is odd in each set. None of them are three odd numbers.
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Found a third set of integers using a^2 + b^2 = 1989 - c^2 for c = 1 thru 44. Nothing is presenting itself as an easier approach than trial and error for the third one. First two were obvious if you know your right triangles.
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89 and 300 are the square of what integer? Also Darth, I think you are not supposed to give actual answers in this area. Not exactly an eligant approach but you can determine that none of the numbers are 45 or greater since the square root of 1989 is 44.598. So you can make 44 equations of A^2 + B^2 = 1989 - C^2 using the values 1-44 for C. Might be easier to spot then. edit - you do much geometry? hint: think of a right triangle with integer sides. I found two with this.
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Love that song!
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Why not? Here is one! Look at me still talking when there's science to do When I look out there, it makes me glad I'm not you I've experiments to run There is research to be done On the people who are still alive
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The first 350 numberas are five digits or less. Are the digits greater than 5 digits after that correct? (Some look like two digits combined)
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I have my action in. Maybe I will get lucky with this one.
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After the game, mind telling me how you figured it out?
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What trap are you talking about? Thinking Hirkala involved? Because the only trap I see is McMasters targeting Hirkala which kind of eliminates that. Oh, are you thinking N1 instead of N2? On N1 Young was the target of McMasters.
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I thought you might be setting up Young as a target for lynching next day. Mention suspicion enough...and hope people forget the night post... Thinking too much. I was thinking that too and thought the odds Ike would target another baddie N1 for a block would be slim so a better chance that Slick would be a goodie. Piece that with Gly "helpfully" telling me not to talk about Young and away I go... And still I can't keep quiet...
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Least I countered the blunder at the end by helping point Gly to Slick in the first place. (See post # 217 on page 22) I think I am just going to be quiet now.
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Could be wrong about AraVer but the night post from N1 said Ike blocked Slick. If they were trying to remove him from suspicion then why didn't they point more to N1 as a defense? Is that another tactic? Just about the same response after D1. What the heck is going on?
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Ike Clanton actually targetted Billy Clanton N1?!? edit - That was my least possible scenerio.
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So gunning for MollyMae, Gly and Onetruth if Slick is a goodie
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For Slick to be a baddie he just about has to be Ike. Otherwise Ike blocked one of their own. If he is Ike then why did AraVer flash vote with no reasoning given at the time of the vote. He had to know it would be questioned. Instead he pointed out my attempt to switch was too late. We will see once maurice tells us.
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I really hope I am wrong and thinking this because of not knowing enough strategy.
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I wish more people were active near the cut off time. All the ones I suspect as baddies currently ( no pun intended ) are the ones being active.
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Since there isn't much activity looks like you all are going to get your way anyways. I still think MollyMae really goofed the night post. That is the only thing I have any concrete evidence of...