bonanova
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Everything posted by bonanova
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Just to tweak things ... What if B, C, D and E were all closer to A then to F? That excludes mirror-image placements.
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Imagine an oversize chessboard. Let the borders of the squares be pathways. So there are nine [not 8] N-S and nine E-W paths, making 81 intersections [4 corners, 28 Ts and 49 4-ways]. I'm standing on the SW corner; you're standing on the NE corner. We start walking toward each other's corner. I walk only in a N or E direction; you walk only in a S or W direction. Assume we start at the same time and walk at equal speeds. What is the probability we will meet? OK, that was easy. Suppose I walk 3 times faster than you. Now what's the probability that we will meet? Remember, we walk on the EDGES of the 8x8 squares, not ON them.
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Yeah - sorry - 6 or fewer. There is at least one fairly common word for this.
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Yup. Nice.
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In the remarkable county of Semicircle, two roads connect the towns of A and F. One road is perfectly straight; and it forms the diameter of the other road - a perfect semicircle. Somewhere along the semicircular road are the towns of B, C, D and E. Remarkably, both A and F towns are an exact number of miles from the other four, as are A and F themselves. That is, the distance from town A to the other five towns is an exact number of miles; the same is true for town F. This could not be true if the straight road were any shorter. What is the distance of town A from town F?
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Usually it takes a consonant and a vowel to make a syllable: CON - SO - NANT; VOW - EL. But some words have fewer than two letters per syllable: A - NE - MO - NE is one example - 7/4 = 1.75 letters / syllable. Can you find any words with at least 4 syllables that use 6 or fewer? There are two with twice as many vowels as consonants. Hint: Count "Y" as a vowel if you pronounce it as such [CA - NA - RY]; as a consonant otherwise [YEL - LOW] Of course I meant 6 or fewer
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Repeat post. Closed.
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Of course not. You're allowed to jest. I do it.
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I would rephrase. Take as many of them as you like, he said, and put them in your bag. Take some: as many as you like, he said, and put them in your bag. Then rely on existential import of "some" to mean she took at least one stone.
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We're pretty sure gravitational pull comes only from the mass within the sphere determined by your distance from the center. Gravitational pull by the mass outside that sphere cancels to zero. I guess that means the bear oscillates forever; but eventually his hair is badly singed.
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Yeah, that's cool. I like the other way [the one about the 3] but to each his own.
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Yes. Once a is found, you know [can find] t. The elegant path to a is being discussed.
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Altitude and [uniform] oblateness are thought of differently, but they similarly affect g: by changing the distance from the earth's center of mass. Agree about the poor bear. Unless the hole goes all the way through. Then he turns a crispy brown.
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Is there a simpler path to a?
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Solve for the number t and the digit represented by a. [3(230 + t)]2 = 492,a04.
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Let's be nice ... Check the 3rd spoiler two posts up.
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Assume Moe collected the rocks Mae did not take and he then finished filling his bag [the 2nd time] from the beach.
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Bingo. Nice going.
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Initial.
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HokieKen, was your spoiler a request?
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Does the fact that 10 m/s represents a velocity rather than an acceleration matter? Logically, If FALSE then ANYTHING is valid. Thus the bear is green.
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OK, you've raised the final point. So let's expand our list of assumptions. Assume Moe filled his bag both times - before and after Mae took some from his first bagful. Assume the stones are of various sizes. Assume when Moe fills his bag, both times, it's equally likely that the bag contains an even or an odd number of stones.
