Followers 0

## 5 posts in this topic

Posted · Report post

This is something I saw somewhere else. Enjoy!

1. The first question with B as the correct answer is:

A. 1

B. 4

C. 3

D. 2

2. The answer to Question 4 is:

A. D

B. A

C. B

D. C

3. The answer to Question 1 is:

A. D

B. C

C. B

D. A

4. The number of questions which have D as the correct answer is:

A. 3

B. 2

C. 1

D. 0

5. The number of questions which have B as the correct answer is:

A. 0

B. 2

C. 3

D. 1

1. C

2. D

3. B

4. C

5. B

0

##### Share on other sites

Posted · Report post

It's a possibility.

1. D

2. B

3. A

4. A

5. D

Those are pretty self-explanatory except for 4. I answered with "A. 3". I justify this with questions 1 and 5 having choice D as the answer and question 3 having D (which is choice A) as the answer. Confused yet?

0

##### Share on other sites

Posted · Report post

And for my second, and more correct, answer:

1. C (This states that the first question with a correct answer of B is #3.)

2. D (This states the answer to #4 is "C. 1".)

3. B (This states that the answer to #1 is C.)

4. C (This states that only one question has an answer of D.)

5. B (This states that there are two questions with correct answers of B.)

First, the more obvious clues:

Question #1 cannot be A or B so either #2, #3, or #2 and #3 must be B. So...

Question #3 cannot be C or D.

Question #4 cannot be D since it would make itself false. So...

Question #2 cannot be A.

Question #5 cannot be A because #1 tells us that at least one question has an answer of B.

Now for trial and error:

Assume the answer to question #3 is A and see how it works out.

#3 is A therefore (remembering our obvious clues) #2 must be B.

#2 is B therefore #1 is D and #4 is A. However, #4 cannot be A because the number of possible correct answers at this time that could be D is 2.

Now start over and assume the answer to question #3 is B and see how it works out.

#3 is B therefore #1 is C.

#2 cannot be A and cannot be B (because #1 says so). If #2 is C, then #4 is B, but #4 cannot be B so #2 is D.

#2 is D therefore #4 is C.

So far, only one question is answered with B (#3), but answering #5 with D messes up #4 and from there #2 until it's all just a huge mess. Answering #5 with B makes itself true.

So, in short:

1. C

2. D

3. B

4. C

5. B

0

##### Share on other sites

Posted · Report post

These answers are impossible: 1A 1B 3D 3C 4D 2A and 5A. Now 1D leads to 2B, 3A, 4A which is impossible. So 1 is C.

1C => 3B

3B [4A, 2B, 5C and 4B are now impossible]

4C

2D

5B

.

0

##### Share on other sites

Posted · Report post

These answers are impossible: 1A 1B 3D 3C 4D 2A and 5A. Now 1D leads to 2B, 3A, 4A which is impossible. So 1 is C.

1C => 3B

3B [4A, 2B, 5C and 4B are now impossible]

4C

2D

5B

.

I was momentarily overjoyed at the prospect of being able to tell you that you are wrong. Then I realized that your questions were not in sequential order. So I must settle for being simply joyed at the fact that we came up with the same answers.

0

## Create an account or sign in to comment

You need to be a member in order to leave a comment

## Create an account

Sign up for a new account in our community. It's easy!

Register a new account