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Honestants and Swindlecants II.


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24 replies to this topic

#1 rookie1ja

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Posted 30 March 2007 - 05:31 PM

Honestants and Swindlecants II. - Back to the Logic Problems
Afterwards he meets another two aborigines. One says: "I am a Swindlecant or the other one is an Honestant." Who are they?

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#2 earl11

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Posted 04 July 2007 - 10:26 AM

Both are Honestants.

Let the one who answered be A and the other one be B.

If A is a Swindlecant, then the statement must be false. Since 'or' is used, both of the clauses should be false.
But, the clause "I am a Swindlecant" would be true. Hence, A cannot be a Swindlecant.
Thus, A is a Honestant.

Now the statement must be true, i.e. either one or both of the clauses should be true.
Case 1. Both clauses are true - This is not possible as "I am a Swindlecant" is obviously false.
Case 2. First clause is true, second is false - Again, not possible, as "I am a Swindlecant" is false.
Case 3. First clause is false, second is true - This case satisfies the conditions as the first clause "I am a Swindlecant" is false. Also the second clause "The other one is a Honestant" could be true.

Hence, as Case 3 is the only one which satisfies the conditions, B is a Honestant too.
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#3 friedpotatos

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Posted 08 July 2007 - 11:51 PM

Both are Honestants.

If A is a Swindlecant, then the statement must be false. Since 'or' is used, both of the clauses should be false.
But, the clause "I am a Swindlecant" would be true. Hence, A cannot be a Swindlecant.
Thus, A is a Honestant.



Then he would be lieing. thus hes not Honestant, flawed.
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#4 collinbullard

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Posted 15 July 2007 - 01:20 AM

Sorry, check your logic. The Honestant has used an 'or' clause, therefore, even if clause 1 (I am a Swindlecant) is false, as long as clause 2 is true, then the entire statement is true. They are both Honestants.
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#5 kabooms1fire

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Posted 17 July 2007 - 12:05 AM

or there both swindlecats, when you use or both statments become linked there for if eatherside of the statement is a lie then the statement itself is a lie.
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#6 m00sej00se

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Posted 25 July 2007 - 04:48 PM

A cannot be a Swindlecant because both of his statements would have to be false to make him a liar. And a liar cannot call himself a liar because he would be telling the truth.

OR (+) truth table (0=false, 1=true)
0 + 0 = 0
0 + 1 = 1
1 + 0 = 1
1 + 1 = 1
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#7 catfishrob

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Posted 28 August 2007 - 06:42 AM

In classical logic form:
A: Person 1 is swidlecat
B: Person 2 is honestant
X= "A xor B"
If A, not X
If not X, not (A + B.)
If A not A (reductio ad absurdum)
---------
Not A (Person 1 not swindlecat)
---------
B (Person 2 is honestant)

Both are honestants.
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#8 aishi_khurana

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Posted 14 November 2007 - 02:09 PM

whaaaat?
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#9 Derfius

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Posted 24 January 2008 - 04:40 PM

Alternate solution: Both are Swidlecats.

Nothing in the original issue stated that they were different...

Derf
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#10 Jackie Chan

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Posted 29 January 2008 - 06:19 PM

Alternate solution: Both are Swidlecats.

Nothing in the original issue stated that they were different...

Derf


That wouldn't work.

In order for the person speaking in this riddle to be a Swindlecant, he would have to be lying. His OR statement, however, is not false and hence not a lie. His OR statement is true! (Why would a Swindlecant say he is a Swindlecant? He lies about everything!)
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