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Posted 28 June 2007 - 01:53 AM
Posted 13 July 2007 - 12:30 AM
Posted 13 July 2007 - 02:49 PM
Of course I like the corner idea too
Posted 14 July 2007 - 12:54 AM
If there is a slight slant in the edges of the moat, then by shoving the bridge into it couldn't they cross?
Or how about using catapults?
Posted 15 July 2007 - 12:50 AM
Could you not also lash 2 footbridges together with a slight overlap to make one longer one?
But then the integrity of the footbridge would be compromised and nobody could guarantee your safety.
Haven't you read Stephen King's "Eye of the Dragon" and the "tension breaking point" theory?
who cares about safety they are conquerors not defenders...and who cant tie two bridges together with 4 feet overlap and not make it safe?
Posted 16 July 2007 - 08:12 AM
Some kids were wandering in the hills when they came across a square medieval castle on a square island. 1 meter from the edge of the walls was a moat - 10 metres wide - filled with foul-smelling water.
(Naturally, the moat has square corners, and the distance from an outer corner to its inner corner is about 14.1 metres wide.)
They found a couple of 9.5 metre planks, but otherwise had no tools to cross the moat. Nevertheless, they figured out a way across. What do you think they did?
Posted 25 July 2007 - 04:06 PM
Posted 26 July 2007 - 07:43 AM
I tried using equations with the two boards at the corner thing and found that there is still .1 meters that aren't acounted for from the outer corner to the inner corner. I'll show my work 'cause with a .1 unnaccounted answer I think I got something backwards and that should be the extra. So see if you can find my fault, please.
Firstly, once they are laid, there will need to be at least 4.6 meters that the bridge forming the triangle will need to cover from the corner to it's central point.
9.5 meter hypotinuse ( I know it's spelled wrong) squared gives you 90.25 meters squared.
(from here on is appr.)This divided by two gives you 45.125 meters squared on each side of the fomed triangle.
I divided by two because the lengths being equal will give you the longest tringle sides and will get you the closest to the castle..
The square root of this gives you 6.7175 meters on each side.
Halfway accross the bridge will be the closest point to the castle and halfway along each side of the formed triangle will line up exactly with the bridge's central point.
So, divide 6.7175 by two to get the distance from land to the bridge's center and you get 3.35 meters.
Note that both sides of the triangle will yield the same answer since they are the same measurments.
3.35 squared plus 3.35 squred gives you 4.73 meters that the hypotinuse bridge covers.
Okay, I guess I just had to go through it again. It does cover it.
For anyone who doesn't think this will work, look at this and prove it wrong.
P.S. I know it is really sloppy and crappy and yes, I did it in paint, but It doesn't change the fact.
Posted 26 July 2007 - 07:51 AM
Posted 26 July 2007 - 03:58 PM
but why do you say 8.5 unit thength of bridge is being used to complete the diagonal bridge when the bridges are 9.5 and not 8.5 meters long?
from the way i read it i assumed that the bridge can only be 9.5 M and only one bridge can be made. Therefore if one 1M was used on the diagonal, only 8.5M of bridge would be able to be made with the remaning material
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