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Josephine


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#21 rookie1ja

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Posted 26 September 2007 - 09:36 AM

This riddle doesn't include any question! The tale is nice, but what's the problem?

The only thing I can do is guess that you want to hear what the tale means:

Here goes:
There were exactly 40 married couples in Mamajorca. Each night since the proclamation, every man slept with another woman than his own, and with another than any of the nights before. On the 40th night, they all came home to sleep with their own wives and were exterminated, thereby dooming the future of Mamajorca, because there would be no more offspring!


BoilingOil


OK ... I guess I have to amend my attitude ... so I will assume that users of my forum can not always find implied questions and they have to be led like little children ... I have moved the questions to the wording of the puzzle
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#22 BoilingOil

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Posted 26 September 2007 - 03:43 PM

OK ... I guess I have to amend my attitude ... so I will assume that users of my forum can not always find implied questions and they have to be led like little children ... I have moved the questions to the wording of the puzzle



It's not as bad as you make it sound now... "BoilingOil" is not "users of your forum". He's only ONE idiot who sometimes doesn't even see the OBVIOUS
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#23 ghici_cn

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Posted 21 October 2007 - 03:16 PM

here is how I see it:
let's suppose there were five cheeting husbands
Wife no5 knows that there are 4 hsbands who cheat and she thinks that Wife no4 only knows about 3 and that she thinks Wife no3 only know about 2... but it's a nonsense to think that any wife in town would believe there are only 2 or 3 unfaithful husbands when in fact there are 5 and all the wives whose husbands cheat on them believe there are 4. So I don't think you can tidy up the induction to 40.
So I think the solution of the puzzle is that every wife asked other wives how many unfathful husbands did they know and if the number was higher than the number they knew, it would mean that their husbands are cheaters too.
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#24 Jeremy

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Posted 20 November 2007 - 06:27 PM

one guy was shot. he was sleaping with a lot of the women and all of them found out the same time then shot him. the queen found out it was her husband.
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#25 al_rawi

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Posted 29 November 2007 - 05:49 PM

Hmm.
how about the wives asking the other men in the village about their husbands? The riddle only talks about wives not allowed to ask other women!

Well, I have to admit that I kind of hunched there was a more "logical" answer, but I stuck to mine :-). (in case ur wondering if the other men would give their friend away so easily, well, I guess they will with a gun pointing to their head :-))
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#26 YoavBa

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Posted 01 December 2007 - 02:46 PM

Josephine - Back to the Logic Puzzles
It is easy to tidy up the induction to show that the n UHs will all be shot just on the n'th midnight.[/spoiler]



It's impossible to "tidy up the induction..." because your logic is absolutly WRONG!!!!!!

If anyone think i'm wrong i would like to see him do it for only 5 unfaithfull husbands!!

btw. i dont know the real answer and if it really exists
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#27 rookie1ja

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Posted 01 December 2007 - 03:56 PM


Josephine - Back to the Logic Puzzles
It is easy to tidy up the induction to show that the n UHs will all be shot just on the n'th midnight.



It's impossible to "tidy up the induction..." because your logic is absolutly WRONG!!!!!!

If anyone think i'm wrong i would like to see him do it for only 5 unfaithfull husbands!!

btw. i dont know the real answer and if it really exists


the logic is absolutely correct ... below is explanation for 1 and 2 unfaithful husbands ... apply the same logic and you will see that if there were 5 unfaithful husbands then all 5 would be shot the 5th night


Spoiler for Solution

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#28 ghici_cn

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Posted 03 December 2007 - 12:53 PM

This is not a proper answer, you just repeated the solution given in the first place!
Yes, the explanation goes well for 1 and 2, unfaithfull husbands, but I'd like to see anyone doing it for only 5 like, I said before!
IT IS IMPOSSSIBLE to assume that if the truth is that there are 40 UHs anyone would think that there were 2 or 3 UHs!
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#29 rookie1ja

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Posted 03 December 2007 - 05:56 PM

This is not a proper answer, you just repeated the solution given in the first place!
Yes, the explanation goes well for 1 and 2, unfaithfull husbands, but I'd like to see anyone doing it for only 5 like, I said before!
IT IS IMPOSSSIBLE to assume that if the truth is that there are 40 UHs anyone would think that there were 2 or 3 UHs!



yes - I repeated the solution, since I assumed that it is clear ... I will try to take it a step further ...

so let's assume that I am a wife and I know that there are 3 UH's

1st night
Let's see if all 3 UH's will be shot ... but nothing happens ... I could have known that ... I guess that each of the 3 wives expected 2 shots ... hmmm, maybe the next night

2nd night
let's wait what happens ... I guess that each of the 3 wives is anxiously awaiting the 2 shots now ... I imagine that one of them might think as follows: "I know there are 2 UH's. They were not shot the first night, since both of the 2 wives thought that there is just 1 UH. So this 2nd night both of them must kill their UH's. What the ...? I hear no shots. And now I know why - not only those 2, but also I do have an UH. We'll shoot them the 3rd night" ... I think that is the way one of the 3 wives might have thought

3rd night
I'll open the window ... time is ticking away and then I hear something ... nope, was just some cat outside ... what is going on here? no shots? it is morning already ... the wives must have thought the way I imagined it ... unless ... wait a minute ... each of them does not know 2 UH's but 3 of them ... so there are 4 UH's? ... but who is the 4th one???
oh noooooo ... where is my gun ...
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#30 twisteddragon

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Posted 03 December 2007 - 06:38 PM

i think u hit it right on the money there. It was hard to follow but i see where your coming from.
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