You have several white cubes and a jug of red paint. Then you use the red paint to cover one or more sides of each cube. Following such a method, how many distinguishable cubes can you make?

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Guest Message by DevFuse

Started by The Turtle Girl, Mar 08 2008 07:10 AM

3 replies to this topic

### #1

Posted 08 March 2008 - 07:10 AM

### #2

Posted 08 March 2008 - 08:18 AM

It seems like it would depend on how you are allowed to go about doing the distinguishing. To explain ...You have several white cubes and a jug of red paint. Then you use the red paint to cover one or more sides of each cube. Following such a method, how many distinguishable cubes can you make?

Spoiler for three possibilities

### #3

Posted 08 March 2008 - 11:26 PM

You have several white cubes and a jug of red paint. Then you use the red paint to cover one or more sides of each cube. Following such a method, how many distinguishable cubes can you make?

Spoiler for looks like

Spoiler for here they are

Nice one.
*The greatest challenge to any thinker is stating the problem in a way that will allow a solution.*

- Bertrand Russell

### #4

Posted 09 March 2008 - 04:00 AM

Ugh. Why didn't I think about placement of sides? Nice job.Spoiler for looks likeSpoiler for here they areNice one.

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