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9 replies to this topic

#1 Sharpie357

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Posted 04 March 2008 - 02:06 AM

Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now?
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#2 thatguyagain

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Posted 04 March 2008 - 02:14 AM

15 and 50
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#3 zeepuzzlemaster

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Posted 04 March 2008 - 06:39 AM

Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now?


Shouldn't it be as Ian is now? Or else it would be impossible.

But 15 and 50
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#4 brhan

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Posted 04 March 2008 - 04:12 PM

Shouldn't it be as Ian is now? Or else it would be impossible.

But 15 and 50


I agree with you, zee.
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#5 heatherlovesjade

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Posted 04 March 2008 - 05:11 PM

this one is killing me- in high school we would have ones like this- ugh- we had powerful calculators as well....
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#6 statman

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Posted 04 March 2008 - 07:49 PM

Spoiler for hmmm

Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now?


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#7 storm

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Posted 05 March 2008 - 03:26 AM

According to your logic....Ian's age=-25yrs
JIll's age=-70yrs.
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#8 Sharpie357

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Posted 11 March 2008 - 12:48 AM

Ummmmmm. . . I got

Spoiler for Ummmm. . . .



I guess I could have messed up, but here's my math:


Spoiler for my math

Edited by Sharpie357, 11 March 2008 - 12:48 AM.

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#9 ladydulac

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Posted 11 March 2008 - 05:33 AM

the problem with you math comes when you look at the statement - in ten years Jill will be four times Ian's age

If Ian = 5 and Jill = 20 then in ten years

Jill = 30 and that is not 4 times Ian's 15

The second equation should have been

Jill + 10 = 4 (Ian + 10) and then you have to distribute and then

Ian = -25 and Jill = -70 which is 5 more than three times Ian's age

and in 10 years

Ian = -15 and Jill = -60 which is four times Ian's age
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#10 Sharpie357

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Posted 11 March 2008 - 10:11 PM

Oh. . . . oops. . . . . . . . :o
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