Guest Report post Posted March 4, 2008 Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now? Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 4, 2008 15 and 50 Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 4, 2008 Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now? Shouldn't it be as Ian is now? Or else it would be impossible. But 15 and 50 Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 4, 2008 Shouldn't it be as Ian is now? Or else it would be impossible. But 15 and 50 I agree with you, zee. Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 4, 2008 this one is killing me- in high school we would have ones like this- ugh- we had powerful calculators as well.... Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 4, 2008 Jill would be -70, and Ian -25 years old. In 10 years, Jill will be -60 and Ian -15. If Ian's age is constant, Ian is 15, so Jill would be 50 and then 60.Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now? Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 5, 2008 According to your logic....Ian's age=-25yrs JIll's age=-70yrs. Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 10, 2008 (edited) Ummmmmm. . . I got Ian=5 Jill=20 I guess I could have messed up, but here's my math: J=Jill E=Ian (so it won't look like ones) J=3E+5 J+10=4E+10 (+10 Because of "in ten years") Then substitute 3E+5+10=4E+10 Then combine like terms 3E+15=4E+10 -10 -10 3E+5=4E -3E -3E 5=Ian's Age Then substitute again J=3(5)+5 J=15+5 J=20 Edited March 10, 2008 by Sharpie357 Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 11, 2008 the problem with you math comes when you look at the statement - in ten years Jill will be four times Ian's age If Ian = 5 and Jill = 20 then in ten years Jill = 30 and that is not 4 times Ian's 15 The second equation should have been Jill + 10 = 4 (Ian + 10) and then you have to distribute and then Ian = -25 and Jill = -70 which is 5 more than three times Ian's age and in 10 years Ian = -15 and Jill = -60 which is four times Ian's age Quote Share this post Link to post Share on other sites
0 Guest Report post Posted March 11, 2008 Oh. . . . oops. . . . . . . . Quote Share this post Link to post Share on other sites
Jill is 5 years older than 3 times as old as Ian. In ten years, Jill will be 4 times as old as Ian. How old are they both now?
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