Suppose that at a certain company, valuable products are stolen over a 4-months periods, presumably by some employee. In the 114 days period, products were stolen in 45 different days. The company keeps a log file of the days the products were stolen. They then looked at the records to see who worked on what day. The following is the contingency table in terms of days for employee A
The evidence looks pretty damning. But you need to convince a judge that it is more than chance. Assume that the chance of product being stolen is binomial and independent for each day with p = 45/114. That is, each day has a 45/114 chance of having product stolen. Calculate the likelihood that A's work days would have the same pattern as above, given the binomial loss assumption. Show your math.
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bushindo
Here's problem from real life.
Suppose that at a certain company, valuable products are stolen over a 4-months periods, presumably by some employee. In the 114 days period, products were stolen in 45 different days. The company keeps a log file of the days the products were stolen. They then looked at the records to see who worked on what day. The following is the contingency table in terms of days for employee A
The evidence looks pretty damning. But you need to convince a judge that it is more than chance. Assume that the chance of product being stolen is binomial and independent for each day with p = 45/114. That is, each day has a 45/114 chance of having product stolen. Calculate the likelihood that A's work days would have the same pattern as above, given the binomial loss assumption. Show your math.
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