[Guest]

6 coins are arranged like so;

--c

c c c c

--c

move one coin to make 4 coins in both rows

edit: now that I've writen it i suddenly realise this is really easy

Edited April 22, 2009 by Omni314

[Guest]

Put far right coin on the center coin:

c

cCc

c

(Editor will not line up the c's, sorry)

Edited April 22, 2009 by vance

[Guest]

Put far right coin on the center coin:

--c

c C c

--c

(Editor will not line up the c's, sorry)

'tis correct (and I've lined it up for you)

[Guest]

'tis correct (and I've lined it up for you)

Thanks.

and the ball is under cup #3.

[Guest]

Put far right coin on the center coin:

c

cCc

c

(Editor will not line up the c's, sorry)

How do you get two rows out of that? I see one row and one column.

[Guest]

How do you get two rows out of that? I see one row and one column.

He had a problem with his computer software. The big C is supposed to to be in the middle and it's composed of two coins on top of each other. At least that's how I understood it.

[Guest]

He had a problem with his computer software. The big C is supposed to to be in the middle and it's composed of two coins on top of each other. At least that's how I understood it.

What tgcat was implying is once the coins are stacked they become a column. You now have 2 rows of 3 coins, 4 columns 1 coin high and 1 column 2 coins high.

[Pickett]

What tgcat was implying is once the coins are stacked they become a column. You now have 2 rows of 3 coins, 4 columns 1 coin high and 1 column 2 coins high.

he meant that:

C C C is a ROW

while

C

C

C

is a column...since rows go left to right, and columns go up and down...that's another explanation of his statement... in which case the solution of

c C c
c

  c  

has 1 ROW of 4 coins, and 1 COLUMN of 4 coins...

[Guest]

here is another explanation that avoids columns

C

(C[CCC)C]

The C's in () make up one row of four and the C's in [] make up a second row of four coins.