Guest Posted March 27, 2009 Report Share Posted March 27, 2009 Use any operator of mathematics like +, -, x, / square under root any thing and solve all the below : _ 1 1 1 = 6 2 2 2 = 6 3 3 3 = 6 4 4 4 = 6 5 5 5 = 6 6 6 6 = 6 7 7 7 = 6 8 8 8 = 6 9 9 9 = 6 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 (edited) 2 + 2 + 2 = 6 (1+1+1)! = 6 (3* 3)- 3 = 6 (4 + 4) - Sqrt (4) = 6 5 + (5/ 5) = 6 (6 + 6) - 6 = 6 7 - (7 / 7) = 6 figuring out the rest.... Edited March 27, 2009 by Nik Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 whattt no one here can solve it or wat? and what is this spoiler Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 you seem to be new to Brainden... we use spoilers here to hide answers from being DIRECTLY/UN-WANTEDLY Visible to other users.... I suggest you read the http://brainden.com/forum/index.php?act=SR&f=7 before posting anything...so you are familiar with the rules...and oh welcome to the den ! PS: You have to click on the button named spoiler to view the answers.... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 adding responses to prev answers... 9 - 4throot(9*9) = 6 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 8 8 8 could be 8^(1/3) + 8^(1/3) + 8^(1/3) * ^(1/3) = 3rd root Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 adding responses to prev answers... 9 - 4throot(9*9) = 6 i didnt get this 4throot(9*9) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 i think u didnt get the question at all "square -under root" lemme explain i think i figured out the first one...it will be something like this sqrt{(1+1+1)square} Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 4throot(9*9) 9*9 = 81 4throot(81) = 3 9-3 = 6 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 i am also confused there is something in the question.. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 I have solved it....Solution.doc Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 1. (1+1+1)!=6 2. 2+2+2=6 3. (3*3)-3=6 4. sqrt(4) + sqrt(4) + sqrt(4)=6 5. (5/5)+5=6 6. 6+6-6=6 7. 7-(7/7)=6 8. 3rdrt(8)+3rdrt(8)+3rdrt(8)=6 9. [sqrt(9)*sqrt(9)]-sqrt(9)=6 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 Thank u all but i didn't get this "!" operator what is it? (1+1+1)! = 6 thank u soo much Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 please tell me the function of ! operator used in answer Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 what is the function of the "!" operator used in answer (1+1+1)!=6 is it not equal to operator? Quote Link to comment Share on other sites More sharing options...
0 Pickett Posted March 27, 2009 Report Share Posted March 27, 2009 what is the function of the "!" operator used in answer (1+1+1)!=6 is it not equal to operator? In mathematics "!" means "factorial"...in programming languages it is often used to mean "not", so that may be where your confusion is coming in...also, I agree, in the way it was posted it looks like they are saying "NOT EQUAL"...but it should be written (1 + 1 + 1)! = 6...or even slightly more separated ((1 + 1 + 1)!) = 6 Basically n! means n * (n - 1) * (n - 2) * ... * 2 * 1 So, for example: 1! = 1 = 1 2! = 2 * 1 = 2 3! = 3 * 2 * 1 = 6 4! = 4 * 3 * 2 * 1 = 24 5! = 5 * 4 * 3 * 2 * 1 = 120 6! = 6 * 5 * 4 * 3 * 2 * 1 = 720 ...etc...etc.. make sense? So, the answer posted (1 + 1 + 1)! = 3! = 3 * 2 * 1 = 6...which is a correct/valid solution. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 i can do 1+1+1 as a trick is it VI as in you push the first two number 1's together in a V shape? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted March 27, 2009 Report Share Posted March 27, 2009 Hmm; (1 + 1 + 1)! = 6 2 + 2 + 2 = 6 (3 + 3 - 3)! = 6 sqrt4 + sqrt4 + sqrt4 = 6 5 + (5/5) = 6 6 + 6 - 6 = 6 7 - (7/7) = 6 3rt(8) + 3rt(8) + 3rt(8) = 6 (sqrt9 + sqrt9 - sqrt9)! = 6 Quote Link to comment Share on other sites More sharing options...
Question
Guest
Use any operator of mathematics like +, -, x, / square under root any thing and solve all the below : _
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6
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