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2 jackets 3 person 30 days 20 each


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[spoiler='There are 2 jackets browed by 3 person for 30 days they decide to wear these jackets 20 days each person how can they do it?

']

Person A wears Jacket 1 for 20 days. After 20 days passes it to Person B. He has had his 20 days.

Person B wears Jacket 2 for 10 days. After 10 days passes it to Person C. Waits 10 days, then gets Jacket 1 from Person A to wear for 10 more days.

Person C wears Jacket 2 for 20 days. He has waited 10 days then had his 20 days wearing Jacket 2.

Person B wears Jacket 1 for 10 days. He has worn Jacket 2 for 10 days and waited 10 days and then worn Jacket 1 for 10 days. He has had his 20 days.

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There are 2 jackets browed by 3 person for 30 days they decide to wear these jackets 20 days each person how can they do it?

There are many, many solutions to this. There are a total of 60 jacket-days (30 days/jacket x 2 jackets). There are 2 people, so each gets 20 of the sixty jacket- days. The sequence is irrelevant.

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There are 2 jackets browed by 3 person for 30 days they decide to wear these jackets 20 days each person how can they do it?

jackets worn on each ten days by them as follows

1-2

1-3

2-3

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2 of the people are conjoined twins which are joined at the torso and have 2 arms. Therefore the 2 jackets will be able to be worn as many times as they want in those 30 days :)

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