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Pretty self explanatory, figure out the next numbers and explain how you got them.

1)1,5,14,30,55,__,__

2)1,2,5,9,34,__,__

3)1,2,3,5,8,3,1,4,5,__,__ (Yes I know I gave you more numbers than before, but I didn't want it to be mistaken with Fibonacci's)

4)99,98,96,93,88,80,__,__

Good Luck!

PS. If someone has already posted these, soory about using them again, but I have not seen them on here or any other logic forum before.

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Pretty self explanatory, figure out the next numbers and explain how you got them.

1)1,5,14,30,55,__,__

2)1,2,5,9,34,__,__

3)1,2,3,5,8,3,1,4,5,__,__ (Yes I know I gave you more numbers than before, but I didn't want it to be mistaken with Fibonacci's)

4)99,98,96,93,88,80,__,__

Good Luck!

PS. If someone has already posted these, soory about using them again, but I have not seen them on here or any other logic forum before.

1) 91, 85 [sum of n squared]

2) stumped me

3) 9, 4 [ (sum of prior two numbers) mod 10 ]

4) 67, 46 [ f(0)=100, f(n)=f(n-1)-fib(n) ]

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Pretty self explanatory, figure out the next numbers and explain how you got them.

1)1,5,14,30,55,__,__

2)1,2,5,9,34,__,__

3)1,2,3,5,8,3,1,4,5,__,__ (Yes I know I gave you more numbers than before, but I didn't want it to be mistaken with Fibonacci's)

4)99,98,96,93,88,80,__,__

Good Luck!

PS. If someone has already posted these, soory about using them again, but I have not seen them on here or any other logic forum before.

1 is adding square numbers

1,5,14,30,55,91,140

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I suppose you say that next item after n will be n+n2.

But 1,2,5... fails since 2+22=6 not 5.

Maybe the given sequence is faulty?

I went with p(n) = p(n-2)^2 + p(n-1)

But I notice that it doesn't work with the start at 1^2 + 2 != 5. <_<

So, assuming that the initial terms aren't purely arbitary (note that they often are in these puzzles), it's back to the pen & paper.

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Pretty self explanatory, figure out the next numbers and explain how you got them.

1)1,5,14,30,55,91,_140_

2)1,2,5,9,34,__,__

3)1,2,3,5,8,3,1,4,5,_9_,4__ (Yes I know I gave you more numbers than before, but I didn't want it to be mistaken with Fibonacci's)

4)99,98,96,93,88,80,67,46__

Good Luck!

PS. If someone has already posted these, soory about using them again, but I have not seen them on here or any other logic forum before.

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