Guest Posted September 14, 2008 Report Share Posted September 14, 2008 three jars with different capacities, 19 Liters (empty), 13 Liters (full of water), 7 Liters (full of water). how can I get two jars with 10 liters of water in a shortest way? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 15, 2008 Report Share Posted September 15, 2008 Pour both the 7 and the 13 into the 19, then pour half of the total of that into the 13. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 15, 2008 Report Share Posted September 15, 2008 Pour both the 7 and the 13 into the 19, then pour half of the total of that into the 13. Good try, and you're close, but if you poured both the 13 and 7 (13+7=20) you would lose 1 liter of water. Unless you want to be the one cleaning up after this (got your towel) then I would try it this way: pour the 7 liters into the 19 liter container. Then pour 3 liters from the 13 liter container into the 19 liter container, which now contains 7 liters. Of course, it isn't easy to just pour an even 3 liters, so just pour and check the heights of both until they are equal. 2 moves, solved. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 15, 2008 Report Share Posted September 15, 2008 three jars with different capacities, 19 Liters (empty), 13 Liters (full of water), 7 Liters (full of water). how can I get two jars with 10 liters of water in a shortest way? the jars do not have scale. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 15, 2008 Report Share Posted September 15, 2008 Good try, and you're close, but if you poured both the 13 and 7 (13+7=20) you would lose 1 liter of water. Unless you want to be the one cleaning up after this (got your towel) then I would try it this way: pour the 7 liters into the 19 liter container. Then pour 3 liters from the 13 liter container into the 19 liter container, which now contains 7 liters. Of course, it isn't easy to just pour an even 3 liters, so just pour and check the heights of both until they are equal. 2 moves, solved. but the jars do not have scale. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 15, 2008 Report Share Posted September 15, 2008 I am not sure this is posted before but anyway below: Let A(19 L), B(13L) and C(7L) Step...............A..........B..........C Initial..............0..........13.........7 1 (C to A) .......7..........13........0 2 (B to A) ......19..........1.........0 3 (A to C) ....12...........1.........7 4 (C to B)......12...........8.........0 5 (A to C)........5...........8.........7 6 (C to B) .......5..........13........2 7 (B to A) ......18...........0........2 8 (C to B).......18..........2.........0 9 (A to C).......11..........2.........7 10 (C to B)......11.........9.........0 11 (A to C).......4..........9.........7 12 (C to B).......4........13.........3 13 (B to A).....17..........0.........3 14 (C to B).....17..........3.........0 15 ( A to C)....10..........3.........7 16 (C to B).....10........10.........0 there are 16 steps minimum. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted September 15, 2008 Report Share Posted September 15, 2008 I am not sure this is posted before but anyway below: Let A(19 L), B(13L) and C(7L) Step...............A..........B..........C Initial..............0..........13.........7 1 (C to A) .......7..........13........0 2 (B to A) ......19..........1.........0 3 (A to C) ....12...........1.........7 4 (C to B)......12...........8.........0 5 (A to C)........5...........8.........7 6 (C to B) .......5..........13........2 7 (B to A) ......18...........0........2 8 (C to B).......18..........2.........0 9 (A to C).......11..........2.........7 10 (C to B)......11.........9.........0 11 (A to C).......4..........9.........7 12 (C to B).......4........13.........3 13 (B to A).....17..........0.........3 14 (C to B).....17..........3.........0 15 ( A to C)....10..........3.........7 16 (C to B).....10........10.........0 there are 16 steps minimum. right, but I'm not sure this is the shortest way? Quote Link to comment Share on other sites More sharing options...
0 rookie1ja Posted September 29, 2008 Report Share Posted September 29, 2008 already posted thread locked Quote Link to comment Share on other sites More sharing options...
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three jars with different capacities, 19 Liters (empty), 13 Liters (full of water), 7 Liters (full of water).
how can I get two jars with 10 liters of water in a shortest way?
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