[soop]

Let's hope I get this one right

Seriously, I've checked this one quite a lot, so it should be ok. But I wouldn't recommend this for non-poker fans.

4 people are playing Texas 5 card hold-em. Assuming they all stay into the end, who wins the pot?

(and what cards do they each have)?

There is one pair on the table (shared cards)

There are two 8's in total

There are three fives in total

There was a 5 on the flop

Player B holds a pair (and is the only player to do so)

The turn card was a Queen.

One player has two clubs.

There are 2 Spades in total

There are 4 of one type of picture card.

There are 6 Picture cards in total.

One player has the Ace of hearts

The highest card Player C has is the Jack of clubs

The lowest card Player A has is the Queen of spades

The river was a Club

One player holds consecutive cards in his hand

Both the 8's are different colours.

Player D holds only red cards

Player B holds no red-suited cards in his hand

There are 3 picture cards on the table (shared cards)

The 8 of diamonds is not present.

There is only one jack in total

Of the 2 non-picture cards on the table, at least one player holds at least one of the same numbered card in his hand.

There are three clubs on the table (shared cards)

Of the pair on the table, (shared cards) they are both different colours (one red, one black).

All the players holding only red cards have different suited cards.

There is a diamond on the table (shared cards)

The river was the second card of a pair on the table

Just to clarify, if a player "holds" cards, that means no-one else can see or use them but that player.

By "on the table" I mean the 5 cards that any of the 4 players can use.

If I say there is a pair on either the table or being held, that does not mean there are only 2 of that card in total.

Edited August 29, 2008 by soop

[Guest]

Player B with a Full House: Queens full of whatever the Shared Pair is (possibly 8's?)

Assuming I'm wrong and I want to think later, when you say that "One player has 2 clubs"--does that mean he 'holds' two clubs (pocket clubs) or between his pocket and the community cards, he has 2 clubs after the flop?

[soop]

Assuming I'm wrong and I want to think later, when you say that "One player has 2 clubs"--does that mean he 'holds' two clubs (pocket clubs) or between his pocket and the community cards, he has 2 clubs after the flop?

Player B with a Full House: Queens full of whatever the Shared Pair is (possibly 8's?)

Your guess was wrong, and yes, I meantr 2 clubs in his hand. If you're stuck later, I'll give you some tips on working it out.

[Guest]

It's not really that I'm stuck, I'm just very bored at work and in a lazy mood...I'm normally good after lunch (3-4 hours from now) but this will probably be solved by then...I'll give it another shot soon when I feel like laying out the scenarios...

[Guest]

Also, I'm assuming that Picture Cards = Face Cards = J, Q, K...is that ok, or are A's included as Picture Cards? And also, no jokers, right?

[Guest]

Here's my guess - based on ace not being a face card:

Board - 5d Kc 8c / Qh / Qc

Player A - Ah Qs

Player B - 5c 5s

Player C - Jc 10c

Player D - Qd 8h

So player D wins with queens full of eights.

[Guest]

A: A(H), Q(S)

B: _©, _(S)

C: J©, 8©

D: 5(H), 6(D)

Flop: 5(D), 8(H), _©

Turn: Q©

River: 5©

This means that C takes it with a Queen High Flush in Clubs (unless the 3rd Flop Card is an Ace, and then it's an Ace High Flush)

Still trying to fill in the gaps to make sure it's right....

EDIT: This can be ignored...I accidentally skipped over the "4 of One Face Card" and noticed after hastily posting and then reviewing...sorry to disappoint

Edited August 29, 2008 by Mumbles140

[soop]

Also, I'm assuming that Picture Cards = Face Cards = J, Q, K...is that ok, or are A's included as Picture Cards? And also, no jokers, right?

Just J Q K, no jokers, aces don't count as picture cards

Edited August 29, 2008 by soop

[soop]

Here's my guess - based on ace not being a face card:

Board - 5d Kc 8c / Qh / Qc

Player A - Ah Qs

Player B - 5c 5s

Player C - Jc 10c

Player D - Qd 8h

So player D wins with queens full of eights.

DING DING DING! That is EXACTLY right!

Well done Sir, the pot belongs to you

[k-man]

A: QS AH (3 queens)

B: 5S 5C (Full House 5/Q)

C: 10C JC (flush)

D: 8H QD (Full House Q/8) - Winner

Table (in order): 5D 8C KC QH QC

Edited August 29, 2008 by k-man

[Guest]

A: A(H) Q(S)

B: 5© 5(S)

C: J© 10©

D: Q(D) 8(H)

A has a 3 Queens, A, K

B has FH (5s Full of Qs)

C has Flush (K High Clubs)

D has FH (Qs Full of 8s)

D wins

[soop]

Looks like we got a split pot