rookie1ja Posted March 31, 2007 Report Share Posted March 31, 2007 No. 20 - Back to the Cryptograms and Algebra Puzzles Replace the same characters by the same numerals so that the mathematical operations are correct. (J+O+I+N+T)*(J+O+I+N+T)*(J+O+I+N+T) = JOINT This old topic is locked since solution is already provided in the Spoiler below. Pls visit New Puzzles section to see always fresh brain teasers. No. 20 - solution (1+9+6+8+3)*(1+9+6+8+3)*(1+9+6+8+3) = 19683 Link to comment Share on other sites More sharing options...
Guest Posted August 31, 2007 Report Share Posted August 31, 2007 If different letters could be the same number, 17576 also works. Interestingly, the cube root of 19683 and 17576 are 27 and 26, respectively. Link to comment Share on other sites More sharing options...
Guest Posted March 15, 2008 Report Share Posted March 15, 2008 very clever Link to comment Share on other sites More sharing options...
Guest Posted May 15, 2008 Report Share Posted May 15, 2008 There might be a technicality against this but 00000, 00001, 00512, 04913, and 05832 should also fit the criteria. Link to comment Share on other sites More sharing options...
Guest Posted May 15, 2008 Report Share Posted May 15, 2008 i think all the other ones that work wouldnt if it said no 2 letters are the same. im not sure if this is implied. the reason they are the cube roots as some1 said is because this can be re-writen as (j+o+i+n+t)3 = JOINT Link to comment Share on other sites More sharing options...
Guest Posted June 13, 2008 Report Share Posted June 13, 2008 There might be a technicality against this but 00000, 00001, 00512, 04913, and 05832 should also fit the criteria. No technicality, the numbers only add to three digits not five, you would have to enter the zeroes yourself which would defeat the point, the numbers have to fit you can not put them where you wish Link to comment Share on other sites More sharing options...
Guest Posted November 24, 2008 Report Share Posted November 24, 2008 No. 20 - Back to the Cryptograms and Algebra Puzzles Replace the same characters by the same numerals so that the mathematical operations are correct. (J+O+I+N+T)*(J+O+I+N+T)*(J+O+I+N+T) = JOINT No. 20 - solution (1+9+6+8+3)*(1+9+6+8+3)*(1+9+6+8+3) = 19683 This is a good one! Can you expand the solution more? Link to comment Share on other sites More sharing options...
Guest Posted October 6, 2010 Report Share Posted October 6, 2010 This is a good one! Can you expand the solution more? PS: My english aint all that Hey Swima, well my answer to that was more logical than other things. (j+o+i+n+t)3= JOINT lets say : j+o+i+n+t = Y Means that if we add those numbers potency 3 = 5 digits Using calculator you realise that the number 22 is the first potency 3 has 5 digits. 22*22*22=10648 the last number is 46 46*46*46= 97336 so we know that the total of the numbers is between 22 and 46. we will check the minimum / maximum sum of five numbers ( j+o+i+n+t) if we do 1+2+3+4+5 = 15 ( not possible as between 22 and 46) 2+3+4+5+6= 20 not possible as between 22 and 46. 3+4+5+6+7= 25 possible, now we know its between 25 and 46 The maximum will be : 9+8+7+6+5= 35 this max so the sum is between 25 and 35. Using calculator you just have to do 25*25*25= 15'625 not good one as number five is shown twice 26*26*26= 15 756 not good one as number five as well is shown more than one time 27*27*27= 19 683 this could be used as total of 1+9+6+8+3= 27 28*28*28= 21 952 not good one as number two is shown twice 29*29*29= 24 389 this could be used however their sum isnt 29 32*32*32= 32 768 this could be used however their sum isnt 32 Hop dat helpd lil bit, as said its more logical than mathematical. Peace m8 Link to comment Share on other sites More sharing options...
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