Guest Posted September 23, 2009 Report Share Posted September 23, 2009 Once again, C=cannibal M=missionary M + M go over. M comes back, picks up another M brings it over, then comes back again to pick up C, brings him over. C comes back over and picks up another C, drops him off and comes back again with the last C. no that is impossible there can NEVERbe more cannibals than missionarys or game over Link to comment Share on other sites More sharing options...
Guest Posted January 21, 2010 Report Share Posted January 21, 2010 (edited) Here is the correct answer 0-cannibles x-missionaries east west XX 000XXX ---------------> X 000X <--------------- X XX 000 --------------> X X 000 <--------------- XX 00 OX ----------------> XX 0X 0X <---------------- 0X 00 XX ----------------> 0X X XXX <--------------- 000 XX X ----------------> 000 x ----------------> 000XX ---------------> 000XXX Is that simple Edited January 21, 2010 by savi Link to comment Share on other sites More sharing options...
Guest Posted December 17, 2010 Report Share Posted December 17, 2010 Alternative Solution:: Cannibals are X's and Missionaries are O's pick up two cannibals: in boat XX leave one cannibal: left side of river X, right side of river X OOO pick up one missionary: in boat XO leave missionary: left side of river XO. right side X OO pick up one missionary: in boat XO leave missionary: left side of river XOO, right side XO pick up one missionary: in boat XO leave missionary: left side of river XOOO, right side of river X pick up cannibal: in boat XX leave both cannibals: left side of the river XXXOOO misonary will die on second stage 2 canibles and one misonary x was there and an xo went there Link to comment Share on other sites More sharing options...
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