Guest Posted May 11, 2010 Report Share Posted May 11, 2010 What are the odds that a grandmother and her grand daughter are both leap year babies (born on Feb 29)? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 (edited) Assuming that leap year occurs once every four years, then the probability is Y^2=(1/(365*4+1))^2. But in reality, there is a leap year every 4 years, unless the year is a multiple of 100 inwhich case it is a common year... unless the year is a multiple of 400 in which case it is a leap year. So the probability of being born on February 29th is X = 1/(366*100+365*300-3). So the probability of both a grandmother and grand-daughter both being born on leap year is X^2. But I would say that the probability of a grandmother having a grand-daugther 400 years younger is 0 (bold assumption) and the probability of having a grand-daughter 100 years young is negligibly close to zero, so their probabilities of being born on leap year are not the same. Based on these assumptions, the probability I come up with is XY Edited May 11, 2010 by Cantor Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 (edited) 2,134,521 to 1 for any two people. The grandmother/grand daughter angle is a red herring. Edited May 11, 2010 by Joey D Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 Assuming that leap year occurs once every four years, then the probability is Y^2=(1/(365*4+1))^2. But in reality, there is a leap year every 4 years, unless the year is a multiple of 100 inwhich case it is a common year... unless the year is a multiple of 400 in which case it is a leap year. So the probability of being born on February 29th is X = 1/(366*100+365*300-3). So the probability of both a grandmother and grand-daughter both being born on leap year is X^2. But I would say that the probability of a grandmother having a grand-daugther 400 years younger is 0 (bold assumption) and the probability of having a grand-daughter 100 years younger is negligibly close to zero, so their probabilities of being born on leap year are not the same. Based on these assumptions, the probability I come up with is XY Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 I see you did ask for odds and not probability so change my answer to (1/XY) : 1 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 Too easy. Y^2=(1/(365*4+1))^2 What are the odds that a grandmother and her grand daughter are both leap year babies (born on Feb 29)? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 Correction to my previous post. X = 397/(366*100+365*300-3). Since there are 397 leap years in a 400 year period. Quote Link to comment Share on other sites More sharing options...
0 Glycereine Posted May 11, 2010 Report Share Posted May 11, 2010 Correction to my previous post. X = 397/(366*100+365*300-3). Since there are 397 leap years in a 400 year period. I think you mean there are 97 leap years in a 400 year period? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 11, 2010 Report Share Posted May 11, 2010 I think you mean there are 97 leap years in a 400 year period? You are correct. That whole counting business always messes me up. Quote Link to comment Share on other sites More sharing options...
0 Glycereine Posted May 11, 2010 Report Share Posted May 11, 2010 You are correct. That whole counting business always messes me up. :-p Quote Link to comment Share on other sites More sharing options...
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What are the odds that a grandmother and her grand daughter are both leap year babies (born on Feb 29)?
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