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kevink2

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Posts posted by kevink2

  1. The radius of the yellow+green circle is sqrt(2)/2. (r^2 = 2/4 = 1/2)

    So the the area of the yellow triangle is 1/4 (b*h*1/2)
    The area of the yellow + green part is 1/4 of the area of the circle (1/4 * pi * 1/2 = pi/8)

    The area of the blue + green areas is half of the area of the circle (1/2 * pi * (1/2)^2 or pi/8)

    So the area of the blue part is (blue+green) - (Yellow + green) + yellow

    Or

    pi/8 - pi/8 + 1/4

    So 1/4

  2. So to sum up:

    for "unanswered, the only individual letters we don't know are s and a, but we know the value for s times a.

    u = 1

    n = 1/9

    a (part of sa)

    n = 1/9

    s: sa is 30 * 9720.0 / sqrt(5)

    w = 1/5.0

    e = 9

    r = 36*sqrt(6)

    e = 9

    d = 30*sqrt(30)

  3. I miss the part where tw=2 (two=2, but I don't think we ever proved o=1)

    Never mind, I figured that part out.

    twenty/two = 10 = enty/o

    10* (en/o) = 10

    en/o=1 en=o

    one=1 and o = ne, each would have to be the square root of 1.

  4. I didn't have time to figure it out all the way, but the answers are not integer, (Also u has to be one)

    sixty/six = ty = 10 -> ty=10

    forty/four = 10 = ty/u

    u-> 1

    twenty/ten = 2 = twy, 2 = two -> o=y

    I had several other letter combinations that equal each other and a few that resolved to actual numbers.

    Hope that helps some.

  5. The basic goal is to cut the space in half with each guess.

    So the first question is is the card 7 or higher (21 cards are 6 or lower, 24 are 7 or higher)

    If the card is 7 or higher, the the next 2 questions are is it 9 and is it 8 (if both answers are "no", then it's a 7)

    If the card is 6 or lower, Ask if the card is 5 or 6. This cuts the space in half(ish) again. Out of the 21 cards that are 6 or lower, 11 are 5 or 6.

    If the card is 5 or 6, use your last question to see if it's 5 (and if not, you know it's 6).

    If the card is 4 or lower (and we only have one more guess), ask if it's 4 (since we have the most of them). If it is, we are good.

    If not, just guess 3 (we have 3 3's and 3 aces and dueses, so you have a 50/50 change).

    In all there is a 100% chance to guess all cards 4 or higher (which is 39/45 of the time). In the other 6/45 times we get it right 50% of the time. The overall average for this is 42/45 times we get it right.

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