[Guest]

OK, while trying to solve the earlier "Tricky Equation" (in the wrong direction I must add), I came up with this one.

Using (most of) the same numbers:

16+53+3+27+7=100

Mathematically, the equation is completely true as written. Nothing needs to be re-arranged, and no numbers, decimal places, base values, or functions need to be changed.

Edited May 23, 2008 by Big Red

[Guest]

It comes out 106..

i don't get what your supposed to do??

[Guest]

It comes out 106..

i don't get what your supposed to do??

You need to show HOW the equation is true- WITHOUT changing any numbers, decimal places, base values, or mathematical functions.

[Guest]

EDIT: Sorry, idiot!

Edited May 23, 2008 by Sedition1917

[Guest]

I don't get it, you say how it is true WITHOUT CHANGING ANYTHING? If you don't change anything the equation is untrue. Something musdt be changed, or explained... EXPLIAN!

[Guest]

Mathematically, the equation is completely true as written. Nothing needs to be re-arranged, and no numbers, decimal places, base values, or functions need to be changed.

A different number base perhaps?? 11ish?

[Guest]

OK, while trying to solve the earlier "Tricky Equation" (in the wrong direction I must add), I came up with this one.

Using (most of) the same numbers:

16+53+3+27+7=100

Mathematically, the equation is completely true as written. Nothing needs to be re-arranged, and no numbers, decimal places, base values, or functions need to be changed.

It's in base 11!!

0,1,2,3,4,5,6,7,8,9,a

[Guest]

It's in base 11!!

0,1,2,3,4,5,6,7,8,9,a

16+53+3+27+7=100

11+6+55+3+3+22+7+7=111

[Guest]

16+53+3+27+7=100

11+6+55+3+3+22+7+7=111

Cancel it. The equation is still wrong in base 11. In base 11, 100=121 in base 10

[Guest]

OK, while trying to solve the earlier "Tricky Equation" (in the wrong direction I must add), I came up with this one.

Using (most of) the same numbers:

16+53+3+27+7=100

We get S+I+Li+Co+N=Fm which is Fermium (Periodic element #100)

Silicon is commonly found as sand, which can be used to make glass -- which is indeed firm.

[Guest]

We get S+I+Li+Co+N=Fm which is Fermium (Periodic element #100)

Silicon is commonly found as sand, which can be used to make glass -- which is indeed firm.

Awesome. If that's not the solution, perhaps it should be.

[Guest]

As I said in the original post, I came up with this one while trying to solve the first Tricky Equation, but I was way off track. This answer is not obtained the same way as the original. Also, it is in decimal (base 10) form.

Think "volume" and "labels".

[Guest]

How about we try spelling them out. In the question it doesn't say as is but "as written" so lets spell it out like this:

sixteen plus fifty-three + three + twenty-seven + seven

ok so we have sixteen plus fifty (minus) three which is 47, then plug it in like so.

16+47+3+27+7=100

16+ 47 = 63 66 93 +7

Edited May 23, 2008 by raphael

[Guest]

Units

If we're adding Litres (I'm Canadian eh) and converting to Quarts:

100L = 106 Quarts (approximately)

[Guest]

One 6+Five 3+3+two 7+7=6+15+3+14+7 = 45 = Four Five = 20 = two 0 = One 00 = 100 "as written"

16+53+3+27+7=100

[Guest]

Units

If we're adding Litres (I'm Canadian eh) and converting to Quarts:

100L = 106 Quarts (approximately)

Jarod's got it.

16 (quarts)+53 (quarts)+3 (quarts)+27 (quarts)+7 (quarts)=106 (quarts)= 100(liters)

[Guest]

Jarod's got it.

16 (quarts)+53 (quarts)+3 (quarts)+27 (quarts)+7 (quarts)=106 (quarts)= 100(liters)

I like mine better , you still changed the formula by adding measurements to it. I still don't get how the other guy went from 2 zeros to 1 and then 2 zeros, where did he get the one from?

Edited May 23, 2008 by raphael

[Guest]

One 6+Five 3+3+two 7+7=6+15+3+14+7 = 45 = Four Five = 20 = two 0 = One 00 = 100 "as written"

16+53+3+27+7=100

I like that one best of the ones posted (including the intended answer )

[Guest]

I like mine better , you still changed the formula by adding measurements to it. I still don't get how the other guy went from 2 zeros to 1 and then 2 zeros, where did he get the one from?

I know the intended answer has already been given, but as with Karl my initial guess was to try a different base. Karl stopped after trying base 11, but it looks to me that base 13 does the trick. I'm not very familiar with non-decimal base arithmetic, so perhaps someone can tell me if this is true:

For Base 13:

16 + 53 = 69

69 + 3 = 6 12

6 12 + 27 = 96

96 + 7 = 100

[Guest]

I know the intended answer has already been given, but as with Karl my initial guess was to try a different base. Karl stopped after trying base 11, but it looks to me that base 13 does the trick. I'm not very familiar with non-decimal base arithmetic, so perhaps someone can tell me if this is true:

For Base 13:

16 + 53 = 69

69 + 3 = 6 12

6 12 + 27 = 96

96 + 7 = 100

in base 13 you get 169 for the 100 and only 135 or something on the left side.

[Guest]

in base 13 you get 169 for the 100 and only 135 or something on the left side.

Can you tell me where I've actually gone wrong in this equation? Let me try to show how I actually worked it out on paper:

16

+53

69

+3

6 12

+27

96

+7

100

So my question is, is this the correct way to do base 13 addition? Again, I'm not very familiar with base-n arithmetic, and this is just how I intuit it working. After some quick googling, it looks like the standard way of notating is to use letters for unrepresented digits, but I'm leaving my example here as I originally thought of it - with those numbers separated by a space in order to distinguish (this may be my first mistake).

[Guest]

Jarod's got it.

16 (quarts)+53 (quarts)+3 (quarts)+27 (quarts)+7 (quarts)=106 (quarts)= 100(liters)

Alright... i got it now

[Guest]

Can you tell me where I've actually gone wrong in this equation? Let me try to show how I actually worked it out on paper:

16

+53

69

+3

6 12

+27

96

+7

100

So my question is, is this the correct way to do base 13 addition? Again, I'm not very familiar with base-n arithmetic, and this is just how I intuit it working. After some quick googling, it looks like the standard way of notating is to use letters for unrepresented digits, but I'm leaving my example here as I originally thought of it - with those numbers separated by a space in order to distinguish (this may be my first mistake).

In this equation, what you have gotten wrong is the fact that you were not working in base 10. I specified that the equation was in decimal (base 10).

As far as if you worked the problem properly for a base 13, I am not sure. I have never worked in base 13, but what you did looks right to me. I have only dealt with bases 2, 10, and 16. If I am adding, I usually convert to decimal and then re convert back to the base I started with.

[Guest]

I know the intended answer has already been given, but as with Karl my initial guess was to try a different base. Karl stopped after trying base 11, but it looks to me that base 13 does the trick. I'm not very familiar with non-decimal base arithmetic, so perhaps someone can tell me if this is true:

For Base 13:

16 + 53 = 69

69 + 3 = 6 12

6 12 + 27 = 96

96 + 7 = 100

That is fine. I'm not saying that mine was the best problem with those numbers, but if you check the original post, I said that there were no base changes. The problem was in decimal...