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## 17 posts in this topic

Posted · Report post

Below given is a blank equation:

____ + ____ = ____

you are given digits 1,2,3,4,5,and 6

Use each only once once without any mathematical operator other than the ones provided in the equation to make this equation true.

Each digit must be used in every solution.

I know of three solutions. Can you provide more?

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Posted (edited) · Report post

Edited by Anza Power
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Posted · Report post

The only way i figured it could go is

##+##=##

because it can't be #+##=### or any other type of combination, but I've tried all possibilities and none was true:

12+34=56 FALSE

12+34=65 FALSE

12+35=46 FALSE

12+35=64 FALSE

12+36=45 FALSE

12+36=54 FALSE

12+43=56 FALSE

12+43=65 FALSE

12+45=36 FALSE

12+45=63 FALSE

12+46=35 FALSE

12+46=53 FALSE

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12+53=64 FALSE

12+54=36 FALSE

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12+56=34 FALSE

12+56=43 FALSE

12+63=45 FALSE

12+63=54 FALSE

12+64=35 FALSE

12+64=53 FALSE

12+65=34 FALSE

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13+24=56 FALSE

13+24=65 FALSE

13+25=46 FALSE

13+25=64 FALSE

13+26=45 FALSE

13+26=54 FALSE

13+42=56 FALSE

13+42=65 FALSE

13+45=26 FALSE

13+45=62 FALSE

13+46=25 FALSE

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13+52=64 FALSE

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14+23=56 FALSE

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14+25=36 FALSE

14+25=63 FALSE

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14+26=53 FALSE

14+32=56 FALSE

14+32=65 FALSE

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15+42=63 FALSE

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21+34=56 FALSE

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23+45=16 FALSE

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23+56=14 FALSE

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23+61=45 FALSE

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23+64=15 FALSE

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23+65=14 FALSE

23+65=41 FALSE

24+13=56 FALSE

24+13=65 FALSE

24+15=36 FALSE

24+15=63 FALSE

24+16=35 FALSE

24+16=53 FALSE

24+31=56 FALSE

24+31=65 FALSE

24+35=16 FALSE

24+35=61 FALSE

24+36=15 FALSE

24+36=51 FALSE

24+51=36 FALSE

24+51=63 FALSE

24+53=16 FALSE

24+53=61 FALSE

24+56=13 FALSE

24+56=31 FALSE

24+61=35 FALSE

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24+63=15 FALSE

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24+65=13 FALSE

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25+13=46 FALSE

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25+14=36 FALSE

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25+16=34 FALSE

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25+34=16 FALSE

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25+36=14 FALSE

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25+46=13 FALSE

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25+61=34 FALSE

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25+63=14 FALSE

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25+64=13 FALSE

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31+24=56 FALSE

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34+65=12 FALSE

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35+12=46 FALSE

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35+16=24 FALSE

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35+21=46 FALSE

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35+24=16 FALSE

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35+46=12 FALSE

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35+64=12 FALSE

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36+12=45 FALSE

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36+14=25 FALSE

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36+15=24 FALSE

36+15=42 FALSE

36+21=45 FALSE

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36+24=15 FALSE

36+24=51 FALSE

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36+42=15 FALSE

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36+45=12 FALSE

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41+23=56 FALSE

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51+34=26 FALSE

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52+31=46 FALSE

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61+23=45 FALSE

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63+12=45 FALSE

63+12=54 FALSE

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63+15=24 FALSE

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63+21=45 FALSE

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63+45=12 FALSE

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63+51=42 FALSE

63+52=14 FALSE

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63+54=12 FALSE

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64+12=35 FALSE

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64+13=25 FALSE

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64+15=23 FALSE

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64+21=35 FALSE

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64+23=15 FALSE

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64+25=13 FALSE

64+25=31 FALSE

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64+32=15 FALSE

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64+35=12 FALSE

64+35=21 FALSE

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64+53=12 FALSE

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65+12=34 FALSE

65+12=43 FALSE

65+13=24 FALSE

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65+14=23 FALSE

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65+21=34 FALSE

65+21=43 FALSE

65+23=14 FALSE

65+23=41 FALSE

65+24=13 FALSE

65+24=31 FALSE

65+31=24 FALSE

65+31=42 FALSE

65+32=14 FALSE

65+32=41 FALSE

65+34=12 FALSE

65+34=21 FALSE

65+41=23 FALSE

65+41=32 FALSE

65+42=13 FALSE

65+42=31 FALSE

65+43=12 FALSE

65+43=21 FALSE

Could we use fractions or dots here? (i.e 16/4, 3.2)

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Posted · Report post

Fractions are not allowed. But you can use the digits in some other manner

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Posted · Report post

4^3 + 1^2 = 65

If you write it in classic mathematical manner, you don't need to use '^' which is used for programming.

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Posted · Report post

4^3 + 1^2 = 65

If you write it in classic mathematical manner, you don't need to use '^' which is used for programming.

One correct ..two more to go

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Posted · Report post

2^5 + 4^1 = 36

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Posted · Report post

2^5 + 4^1 = 36

one more to go

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Posted · Report post

Most of them involve 1 raised to any power is still 1

1^234+5=6

1^236+4=5

1^243+5=6

1^2+4^3=65

1^256+3=4

1^263+4=5

1^265+3=4

1^324+5=6

1^326+4=5

1^342+5=6

1^362+4=5

1^423+5=6

1^432+5=6

1^4+35=6^2

1^456+2=3

1^465+2=3

1^526+3=4

1^546+2=3

1^562+3=4

1^564+2=3

1^623+4=5

1^625+3=4

1^632+4=5

1^645+2=3

1^652+3=4

1^654+2=3

2^5+4^1=36

2^5+4=36^1

35+1^4=6^2

4^1+2^5=36

4^3+1^2=65

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Posted · Report post

Well i'm stumped.

Every possible combination and didn't get anything.

I'm thinking that we need to switch to a different base to make the equation true. Base 6? I'll have to get back to this one.

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Posted · Report post

Below given is a blank equation:

____ + ____ = ____

you are given digits 1,2,3,4,5,and 6

Use each only once once without any mathematical operator other than the ones provided in the equation to make this equation true.

Each digit must be used in every solution.

I know of three solutions. Can you provide more?

Isn't raising a number to a power (i.e., exponents) a mathematical operation, too? Yet, you say not other mathematical operations, and even say that fractions aren't allowed. Maybe I'm just too new, but this is confusing.

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Posted · Report post

Isn't raising a number to a power (i.e., exponents) a mathematical operation, too? Yet, you say not other mathematical operations, and even say that fractions aren't allowed. Maybe I'm just too new, but this is confusing.

I think it's because you don't need to write an operator, just the exponent. It's a little confusing, but I guess that was his intention. He wrote "operator" and we assumed "operation".

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Posted · Report post

4^(1+3)=256

I think i have it

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Posted · Report post

You need to change the base.

14+36=52 Base 8

15+26=43 Base 8

16+25=43 Base 8

16+34=52 Base 8

24+35=61 Base 8

25+16=43 Base 8

25+34=61 Base 8

26+15=43 Base 8

34+16=52 Base 8

34+25=61 Base 8

35+24=61 Base 8

36+14=52 Base 8

I tried a bunch of other bases, and base 8 is the only one that works.

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Posted (edited) · Report post

One correct ..two more to go

You told not to use any mathematical operator than + and == so ^ is also a mathematical operastor. Isnt it?

Edited by parik
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Posted · Report post

You told not to use any mathematical operator than + and == so ^ is also a mathematical operastor. Isnt it?

you are considering this operator thing too seriously..this is just rearranging the digits in another manner

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Posted · Report post

Solved by Hugo and others

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