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# Pouring water I.

48 replies to this topic

### #31 chu121su12

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Posted 29 February 2008 - 09:45 PM

My first answer was the 3-litre bowl method. But, just tought to the details:

Half method
You get 4 litres, without spilling any water. Inaccuracy: paralax measurement

3-litre bowl method
Wasting 5 litres, you get 4 litres

5-litre bowl method
Wasting 3 litres, you get 7 litres
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### #32 savvyrose88

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Posted 13 March 2008 - 12:29 PM

Pour water in half of each bowl. So you have 1.5 litre ( 3Litre bowl) 2.5 ( 5 litre bowl)
Then pour the 1.5 litre on the 2.5 litre, thus you have 4 litre. <!-- s:lol: --><!-- s:lol: -->

Why not just fill the 3L bowl then pour that into the 5L bowl then add 1L to the 3L and pour that into the 5L bowl...there's 4L

But, if they are marked...Find the 4L mark on the 5L bowl and fill it to that mark...LOL....again, there's 4L
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### #33 kiger

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Posted 17 March 2008 - 04:53 AM

Perhaps a few more steps--more wasting of water too. But it works.
1) Fill the 3. Pour it into the 5.
2) Fill the 3 again. Pour 2 into the 5. 1 remains in the 3.
3) Empty the 5. Pour the 1 from the 3 into the 5.
4) Fill the 3 again. Pour it into the 5 that already has 1 in it. Voila!

thats how i did it
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Posted 01 April 2008 - 12:02 PM

You can't mark the water line since this is not exact. Do the following:

1. Fill 5 liter and pour into 3 liter container leaving 2 liters (in the 5 liter container)
2. Empty 3 liter container (no rules about emptying out water) and pour the 2 liters from the 5 into the 3 liter container leaving 1 liter of head space.
3 Fill 5 liter and pour as much as the remainder of the 3 liter will handle (1 liter from step 2) leaving 4 liters exactly in the 5 liter contain. Drink the rest of the water in the 3 liter container

Yours is the best answer I've seen so far.
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### #35 BillyAsh

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Posted 13 April 2008 - 08:54 AM

Doesn't work that way. If you were able to pour out only 2 units of water from the 3 unit bowl (as stated in line 2) then why not just do that twice, and you would have 4 parts. Point of the riddle is that you are not able to Eyeball 2 parts (meaning the bowls must not be marked or there would be no point for the riddle) You need to figure out a way to accurately measure 4 parts Without Guesswork...

Best I can figure is like this.

Fill the 5 unit bowl. Fill the 3 unit bowl from the 5 unit bowl leaving 2 units in the 5 unit bowl. Mark the 2 unit water line in the 5 unit bowl. Empty the 3 unit bowl. Transfer the pre measured 2 units from bowl 5 into bowl 3. Now bowl 3 has 2 units of water in it for sure! Refill the 5 unit bowl to your mark (2 units) and the dump the other 2 units in the other bowl into that one. B. I. N. G. O and BINGO was her NAME-----O

But that's assuming that you were able to mark the bowls, and I do not think that that is allowed in the rules. So it's still not really valid..lol

I am sorry but it does work that way Veracity.
The reason that it is possible to pour out only two units on line 2 is because there is already 3 units in the 5 unit bowl because you poured 3 units in it the first line. If there is already three units in the 5 unit bowl then obviously you can only pour another 2 units into it. At no point does there need to be any marking for 2 units - this person has it worked out different to the answer given and is totally correct. If you pour 2 units out of 3 units that leaves 1 unit - empty the five unit bowl - put the one unit in it and then add 3 more units from the 3 unit bowl - well done loserfreak!

I agree with both methods.
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### #36 Cute e pie

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Posted 14 April 2008 - 09:03 PM

2 e.z.
just take the 5 liter container, fill and pour 3 liters into the 3 liter container.
Empty remaining water into bowl.
Repeat.
presto.
the bowl has 4 liters.

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### #37 Milind Shende

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Posted 25 April 2008 - 12:08 PM

there could be other solution to this problem.

1) Fill the 5. Pour it into the 3. so 5 has 2 ltrs in it.
2) Empty 3. pour 2 ltrs from 5 to 3.
3) Fill 5. then pour 5 to 3, 3 needs only 1ltr to become full.
4) So, in 5, we will have exactly 4ltrs. Yooooohoooooo !!!!

regards,
Milind.
______________________________________________________

Doesn't work that way. If you were able to pour out only 2 units of water from the 3 unit bowl (as stated in line 2) then why not just do that twice, and you would have 4 parts. Point of the riddle is that you are not able to Eyeball 2 parts (meaning the bowls must not be marked or there would be no point for the riddle) You need to figure out a way to accurately measure 4 parts Without Guesswork...

Best I can figure is like this.

Fill the 5 unit bowl. Fill the 3 unit bowl from the 5 unit bowl leaving 2 units in the 5 unit bowl. Mark the 2 unit water line in the 5 unit bowl. Empty the 3 unit bowl. Transfer the pre measured 2 units from bowl 5 into bowl 3. Now bowl 3 has 2 units of water in it for sure! Refill the 5 unit bowl to your mark (2 units) and the dump the other 2 units in the other bowl into that one. B. I. N. G. O and BINGO was her NAME-----O

But that's assuming that you were able to mark the bowls, and I do not think that that is allowed in the rules. So it's still not really valid..lol

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### #38 firepumpguy

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Posted 03 May 2008 - 11:08 PM

I think instead of using "water" we should be using "gold dust." And it's your gold dust you're pouring in to the bowls and jars. Maybe there wouldn't be any more "eye balling" levels and no more "over spill."

Edited by firepumpguy, 03 May 2008 - 11:11 PM.

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### #39 firepumpguy

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Posted 04 May 2008 - 02:32 AM

5 & 3 size bowls, resolve 4

A=5 size
B=3 size

A - B
is
0 - 0

Fill A(+5)
5 - 0

Pour A(-3) in to B(+3)
2 - 3

Dump B(-3)
2 - 0

Pour A(-2) in to B(+2)
0 - 2

Fill A(+5)
5 - 2

Pour A(-1) in to B(+1)
4 - 3
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### #40 monkle

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Posted 10 June 2008 - 02:07 PM

Perhaps a few more steps--more wasting of water too. But it works.
1) Fill the 3. Pour it into the 5.
2) Fill the 3 again. Pour 2 into the 5. 1 remains in the 3.
3) Empty the 5. Pour the 1 from the 3 into the 5.
4) Fill the 3 again. Pour it into the 5 that already has 1 in it. Voila!!

this way is correct
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