Guest Posted August 13, 2009 Report Share Posted August 13, 2009 Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of cryptarithmetic equations. Each of U, E and B is nonzero. ABT = (UBA)C and, UIC = (ETE)O and, TBN = (BYO)Y Note: BT, UBA, .... represent the concatenation of the digits, rather than the product of the digits. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 13, 2009 Report Share Posted August 13, 2009 This looks harder then it really is Start with UIC = (ETE)O It's the easiest part of the three A=9, B=2, C=8, E=3, I=1, N=0, T=4, U=7, Y=5, O=6 Quote Link to comment Share on other sites More sharing options...
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Substitute each of the letters by a different digit from 0 to 9 to satisfy this system of cryptarithmetic equations. Each of U, E and B is nonzero.
ABT = (UBA)C and, UIC = (ETE)O and, TBN = (BYO)Y
Note: BT, UBA, .... represent the concatenation of the digits, rather than the product of the digits.
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